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erastova [34]
3 years ago
5

Any help? I'm struggling.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer:

Step-by-step explanation:

a=-7

r=21/-7=-3

a_{15}=a r^{n-1}=-7(-3)^{15-1}=-7(-3)^{14}=-33480783

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Which three lengths
Tanya [424]

Answer:

B)

Step-by-step explanation:

You need to add the first 2 numbers and the answer needs to be bigger than the third number and if you add 10 + 5 will be 15 and the third number is 17, so the answer of this is the B

3 0
3 years ago
HELP!!! will give brainliest!!!! i dont know how to do this
netineya [11]
I'm attaching the solutions.. please let me know if you have any questions.

Hope it helps.

8 0
3 years ago
Which values of x are solutions to the inequality? 12 ≥ 4x – 3(6 + 2x)
Dmitry_Shevchenko [17]

Answer:

-15

Step-by-step explanation:

4 0
2 years ago
A manufacturer knows that their items have a normally distributed length, with a mean of 13.1 inches, and standard deviation of
Afina-wow [57]

Answer:

0.73% probability that their mean length is less than 11.1 inches

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 13.1, \sigma = 4.1, n = 25, s = \frac{4.1}{\sqrt{25}} = 0.82

What is the probability that their mean length is less than 11.1 inches

This is the pvalue of Z when X = 11.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.1 - 13.1}{0.82}

Z = -2.44

Z = -2.44 has a pvalue of 0.0073.

0.73% probability that their mean length is less than 11.1 inches

3 0
4 years ago
2m² + 2m – 12 = 0<br>m=? <br>a. 2,-12 <br>b. 3,1 <br>c. 1.-3 <br>d. -2.2​
sammy [17]

Step-by-step explanation:

F1/A1 = F2/A2

10/2=F2/4

5=F2/4

F2=5x4

F2=20

4 0
2 years ago
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