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SpyIntel [72]
3 years ago
14

DIG DEEPER At a restaurant, when a customer buys 4 pretzels, the fifth pretzel is free. Soft pretzels cost $3.90 each. You order

12
soft pretzels. What is your mean cost per pretzel?
The mean cost is $
per pretzel.
Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0
3.25$ per pretzel. Buying 12 pretzels gets you two free pretzels which is 7.80$ worth of pretzels. 3.90x12= $46.80
46.80-7.80= $39.00
39/12= 3.25 per pretzel
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7 lbs of sour candies cost $7.00. What is the unit price?
grandymaker [24]

Answer:

$1 per lb

Step-by-step explanation:

If you divide the cost by the amount you are getting, then you get the unit rate. So, since 7 divided by 7.00 is 1.00, then the cost per pound is $1.00

7 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
51450÷98 can u show me how
Andreas93 [3]

51450 divided by 98
is 525 with remainder 0


0 0 5 2 5
9 8| 5 1 4 5 0
0
5 1
0
5 1 4
4 9 0
2 4 5
1 9 6
4 9 0
4 9 0
0
7 0
3 years ago
Find two numbers a and b such that a+b=0 and ab=36
PolarNik [594]

Answer:

b = 6i   then a = -6i

b = -6i   then a = 6i

Step-by-step explanation:

a+b=0

ab=36

a = -b

a(b) = 36

-b * b = 36

- b^2 = 36

b^2 = -36

Take the square root of each side

sqrt(b^2) = sqrt(-36)

b =± 6i

a = - (± 6i)

so b = 6i   then a = -6i

b = -6i   then a = 6i

4 0
3 years ago
Find (f – g)(x) if f(x) = 2x – 3 and g(x) = 4x + 8.
Aleks04 [339]

f(x) - g(x) = 2x-3 -(4x+8)

              = 2x-3 -4x-8

               = -2x-11

4 0
3 years ago
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