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denpristay [2]
3 years ago
15

Please help me with my question ASAP ASAP please ASAP

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

D

Step-by-step explanation:

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Find the absolute maximum value of the function (picture shown)
hammer [34]

Answer:

  1

Step-by-step explanation:

The maximum on the first interval is at x=0, where 2·0 +1 = 1.

The maximum on the second interval is near x=0, where the function value is near 0² +1 = 1.

The absolute maximum value of the function is 1.

3 0
4 years ago
2x + 6y= 386<br> 4x +4y=292
Vilka [71]

Answer:

x = 13  ,y = 60

Step-by-step explanation:

Solve the following system:

{2 x + 6 y = 386 | (equation 1)

4 x + 4 y = 292 | (equation 2)

Swap equation 1 with equation 2:

{4 x + 4 y = 292 | (equation 1)

2 x + 6 y = 386 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{4 x + 4 y = 292 | (equation 1)

0 x+4 y = 240 | (equation 2)

Divide equation 1 by 4:

{x + y = 73 | (equation 1)

0 x+4 y = 240 | (equation 2)

Divide equation 2 by 4:

{x + y = 73 | (equation 1)

0 x+y = 60 | (equation 2)

Subtract equation 2 from equation 1:

{x+0 y = 13 | (equation 1)

0 x+y = 60 | (equation 2)

Collect results:

Answer: {x = 13  ,y = 60

3 0
3 years ago
Whats 1100 x 100,00 pls help
sweet-ann [11.9K]

Answer:

110000

Step-by-step explanation:

4 0
3 years ago
Consider the 6 x 9 inch rectangular cake that is 2 inches deep. If you cover the cake with frosting excluding the bottom, what i
Olenka [21]

Total area of the ends: 2(2")(6") = 24 in^2

Total area of the sides: 2(2")(9") = 36 in^2

Are of the bottom : 1(6")(9") = 54 in^2


Total surface area to be covered = (24+36+54) in^2

7 0
3 years ago
Read 2 more answers
multiply (5x^2 x − 4)(x 2). 5x^3 x^2 − 4x − 8 5x^3 11x^2 − 2x − 8 5x^3 10x^2 − 4x − 8 5x^3 20x^2 2x − 8
Ulleksa [173]
(5x^2 + x - 4)(x + 2) = x(5x^2 + x - 4) + 2(5x^2 + x - 4) = 5x^3 + x^2 - 4x + 10x^2 + 2x - 8 = 5x^3 + 11x^2 - 2x - 8
3 0
3 years ago
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