Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
The line segment that is a radius is FD.
Hope it will help:)❤
Answer:
2(n+2x-6)
Step-by-step explanation:
n x 2+4x-4-8
<h2>
Answer:</h2>
4.82 × 10⁻⁴
<h3>
Explanation:</h3>
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Answer:
Step-by-step explanation:
We have been given the expression:
We will use the property:
Here, 
So, we will get from the identity:
Hence, you are not right because you removed square rrot in final result rest is right.
