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2 years ago

Write the equation of the line that passes through the points (-9, -7)

Mathematics

1 answer:

dybincka [34]2 years ago

6 0

Answer: y= (11/5)x+(64/5) or y=(11x+64)/5

Step-by-step explanation:

(y-y1)/(x-x1)=(y2-y1)/(x2-x1)

x1= -9, x2= -4

y1= -7, y2= 4

(y-(-7))/(x-(-9))=(4-(-7))/(-4-(-9))

(y+7)/(x+9)=(4+7)/(-4+9)

(y+7)/(x+9)=11/5

Cross multiply

5(y+7)=11(x+9)

5y+35=11x+99

5y=11x+99-35

5y=11x+64

y=(11x+64)/5

y=(11/5)x+(64/5)

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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

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Plz help !!!!!!!!!!!!!

Serhud [2]

I not 100% sure but I chose C.

Hope this helps.. but good luck :)

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