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alexira [117]
3 years ago
12

Give three real-world examples of rectangular prisms. Then give two real-world examples of triangular prisms. Explain how you kn

ow the object you chose represents a prism.​
Mathematics
2 answers:
Vikki [24]3 years ago
4 0

Answer:

Sample response: Boxes, ice cubes, and a brick are examples of rectangular prisms. Ramps and tents are examples of triangular prisms. A rectangular prism has six rectangular faces. A triangular prism has two triangular faces and three rectangular faces.

Step-by-step explanation:

i tried

denpristay [2]3 years ago
3 0

Three real world examples of rectangular prisms include juice boxes, cereal boxes, and even cargo containers. Two real world examples of triangular prisms include camping tents and triangular roofs. I chose these objects to represent triangular and rectangular prisms because triangular prisms have two triangular faces and three rectangular faces and rectangular prisms have six rectangular faces.

Sample Response: Boxes, ice cubes, and brick are examples of rectangular prisms. Ramps and tents are examples of triangular prisms. A rectangular prism has six rectangular faces. A triangular prism has two triangular faces and three rectangular faces.

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The cost of 5m of cloth is ₹450. The cost of 8m of cloth is
enyata [817]

Step-by-step explanation:

Rs 720

Cost of 1 m of cloth = 450/5= Rs 90

Cost of 8 m of cloth= 90*80= Rs 720

7 0
3 years ago
Read 2 more answers
A 99% confidence interval for the mean μ of a population is computed from a random sample and found to be 6 ± 3. We may conclude
valentina_108 [34]

Answer:

A. there is a 99% probability that μ is between 3 and 9.

Step-by-step explanation:

From a random sample, we build a confidence interval, with a confidence level of x%.

The interpretation is that we are x% sure that the interval contains the true mean of the population.

In this problem:

99% confidence interval.

6 ± 3.

So between 6-3 = 3 and 6 + 3 = 9.

So we are 99% sure that the true population mean is between 3 and 9.

So the correct answer is:

A. there is a 99% probability that μ is between 3 and 9.

4 0
3 years ago
Read 2 more answers
PLEASE help ASAP will give brainlist
alex41 [277]

Answer:

if im not mistaken it would be 6

Step-by-step explanation:

because you half the 18

8 0
2 years ago
Round 8.47285 to 3 decimal places
Elanso [62]
8.473 is the correct answer
7 0
3 years ago
A random sample of 40 binomial trials resulted in 14 successes. test the claim that the population proportion of successes does
mylen [45]

Using the z-distribution, since the p-value of the test is of 0.057 > 0.05, there is not enough evidence that the population proportion of successes does not equal 0.50.

<h3>What are the hypotheses tested?</h3>

At the null hypotheses, we test if the proportion of successes equals 0.5, hence:

H_0: p = 0.5

At the alternative hypotheses, we test if it does not equal, hence:

H_1: p \neq 0.5

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are given by:

n = 40, \overline{p} = \frac{14}{40} = 0.35, p = 0.5

Hence the test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = (0.35 - 0.5)/(0.5/sqrt(40))

z = -1.9.

<h3>What is the decision?</h3>

Using a z-distribution calculator, considering a two-tailed test, as we are testing if the proportion is different of a value, with z = -1.9, we get that the p-value of the test is of 0.057.

Since the p-value of the test is of 0.057 > 0.05, there is not enough evidence that the population proportion of successes does not equal 0.50.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ4

5 0
1 year ago
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