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3 years ago

Please help me I will def give brainliest <3

Mathematics

1 answer:

stealth61 [152]3 years ago

7 0

Answer:

1) 10:1:3

2)a. Soup-20 oz. Cheese-2 cups, Pasta-6 cups

2)b. Soup-5 oz. Cheese-1/2 cup, Pasta-1 1/2 cups

2)c. Soup-50 oz. Cheese-5 cups, Pasta-15 cups

2)d. Soup-2 oz. Cheese- 1/5 cup, Pasta-3/5 cup

3) 3:6 = 1:2

4)a. 3 batches

4)b. 6 batches

4)c. 1/2 batch

Elaboration

1) Yes, because it simplifies down to 5:3.

2) Yes, because it also simplifies down to 5:3.

3) 25:15 and 35:21

4) If they share a zoom factor then they are equivalent.

5) Equivalent ratios are ratios that make the same comparison of numbers.

Evaluation

1) 2:3

2) They are equivalent because they share a zoom factor of 2.

Last Page

4)a. 28 oz of cream cheese. (35*0.8)

4)b. 4.8 weeks (1.6*3)

4)c. $4,000 (4*1,000)

Evaluation

1) 2 lbs-$6, 0.33 lbs-$1, 1 lbs-$3

2) 0.33 is the amount in pounds that you can get at the price of $1, and 1 pound of grapes will cost $3

You might be interested in

“six less than twice y”

jonny [76]

Answer:

2y-6

Step-by-step explanation:

Six less = Subracted by 6.

7 0

4 years ago

F(x) = 2x + 2 and g(x) = 7x + 1, which composition produces the greatest output

lora16 [44]

The correct answer would be g(x).

Notice that g(x) has a greater slope than f(x), which would make the line, if it were to be graphed, steeper, which means it increases at a faster rate.

To prove that g(x) has a greater output, you can plug in values into x to see which equation has the greater output.

Let's start with the number 1:
2(1)+2=4
7(1)+1=8

Then you can try other numbers such as 10 to see if this trend continues:
2(10)+2=22
7(10)+1=71

As you have seen, g(x) appears to have the greater output.

Hope this helps!

4 0

3 years ago

If a pair of regular dice are tossed once, use the expectation formula to determine the expected sum of the numbers on the upwar

Darya [45]

Answer:

The expected sum of the numbers on the upward faces of the two dice is 7.

Step-by-step explanation:

Consider the provided information.

If two pair of dice tossed the possible out comes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6,6)

Now we need to find the expected sum of the numbers on the upward faces of the two dice.

The expected sums can be:

Sum: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

Prob: 1/36, 2/36, 3/36, 4/36, 5/36, 6/36, 5/36, 4/36, 3/36, 2/36, 1/36

As we know that the expectation of experiment can be calculated as:

$P(S_1)\cdot S_1+P(S_2)\cdot S_2+........+P(S_n)\cdot S_n$

Here S represents the numerical outcomes and P(S) is the respective probability.

Substitute the respective values in the above formula.

$=2\times\frac{1}{36}+3\times\frac{2}{36}+4\times\frac{3}{36}+5\times\frac{4}{36}+6\times\frac{5}{36}+7\times\frac{6}{36}+8\times\frac{5}{36}+9\times\frac{4}{36}+10\times\frac{3}{36}+11\times\frac{2}{36}+12\times\frac{1}{36}\\=\frac{252}{36}\\=7$