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sdas [7]
2 years ago
11

A rectangular swimming pool measures 7.5 m by 4.5 m. It is completely surrounded by a fence parallel to each edge of the pool an

d at a distance of 3 m from each edge of the pool.
Calculate the total length of the fence.
Mathematics
1 answer:
Illusion [34]2 years ago
4 0

The total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

<h3>What is rectangle?</h3>

It is defined as the two-dimensional geometry in which the angle between the adjacent sides are 90 degree. It is a type of quadrilateral.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that:

A rectangular swimming pool measures 7.5 m by 4.5 m.

It is completely surrounded by a fence parallel to each edge of the pool and at a distance of 3 m from each edge of the pool.

The total length of the fence = 2(7.5+3×2 + 4.5+3×2)

The total length of the fence = 2(7.5+6 + 4.5+6)

The total length of the fence = 2(24)

The total length of the fence = 48 m

Thus, the total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

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Step-by-step explanation:

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Read 2 more answers
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
Mike went to a football game with his family. They bought 5 boxes of popcorn and 3 programs, and spent $41. Sean's family went t
slamgirl [31]
EZ!

Let's say each box costs $X and each program costs $Y
Thus, Mike's family spent:
$(5X+3Y)
or
$41

Sean's family spent
$(3X+2Y)
or
$26

This yields us a system of two equations:
5x+3y=41
3x+2y=26

<span>5x+3y=41
</span>2y=26-3x

<span>5x+3y=41
</span><span>y=13-1.5x
</span>
5x+3(13-1.5x)=41
y=13-1.5x

5x+39-4.5x=41
<span>y=13-1.5x
</span>
0.5x+39=41
<span>y=13-1.5x
</span>
0.5x=2
<span>y=13-1.5x
</span>
x=4
<span>y=13-1.5x
</span>
x=4
<span>y=7
</span>
Each box costs $4 and each program costs $7
8 0
3 years ago
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