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3 years ago

i have 110,000 rolls of film. Each film weighs 4.70 ounces. How much would it cost me to have them moved at $.046 per pound?

Mathematics

1 answer:

liraira [26]3 years ago

8 0

Take110,000x4.70=517,000 take that and divide by 16=32312.5 pounds and multiply by .046=1486.375$

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2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

Find the circumcenter of (6, -3) (-7, 6) (6, 6)

kirill115 [55]

<h3>Answer:</h3><h3>(-0.5, 1.5)</h3>

Step-by-step explanation:

7 0

3 years ago

Brenda has a circular garden of radius 21 m . She ran round the garden twice .what distance did she cover

Pavlova-9 [17]

Answer:

Brenda ran 263.76 metres.

Step-by-step explanation:

The circumference of a circle is two times pi times its radius. Brenda rand that twice, so we need:

2 × 2πr

= 4πr

= 4 × 3.14 × 21m

= 263.73m

4 0

3 years ago

Solve the equation. -15=a/5 <br> A. a= -3<br> B. a= -20<br> C. a= -10<br> D. a= -75

kap26 [50]

-15=a/5
well first you would multiply by each side, with a result of
-75=a

so D

8 0

3 years ago

Read 2 more answers

IS THERE A LOST GENIUS OUT THERE THAT CAN HELP ME??????

Gelneren [198K]

If i can remember, a direct variation is y=kx so find y and x, and you can figure out k. i’m probably wrong, good luck tho! lol

4 0

3 years ago