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2 years ago

PLEASE help it would mean the world to me it would help so much please and thank you

Mathematics

1 answer:

castortr0y [4]2 years ago

3 0

Area = 18 = 1/2 x 6 x (h+1)
h=5

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What is the value of 7(10 - 2^3) + 8 divided by 2

Zielflug [23.3K]

$7(10-2^3)+8 \div 2 \\ \\ 7(10-8)+8 \div 2 \\ \\ 7(2)+8 \div 2 \\ \\ 7(2)+4 \\ \\ 14+4 \\ \\ \boxed{18}$

5 0

2 years ago

17. Mrs. Marshall baked 120 cookies. She decided

agasfer [191]

Answer:

20 cookies

Step-by-step explanation:

120*6=20

20 = 1/6 of 120

8 0

3 years ago

HELP AND THEY ARE all Diffrent questions

Anarel [89]

Answer:1)720 white stripes and 840 red stripes

2)48 divided by 4=12 feett per second

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4)3 times 10=30

Step-by-step explanation:

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2 years ago

Read 2 more answers

If five times the successor of a number is added to an original number the sum is 83

Alexus [3.1K]

Answer:

Let the original number be x

Successor is defined as the number which comes immediately after a particular number.

also, the successor of a whole number is the number obtained by adding 1 to that number.

Then, the successor of a number x is, x+1

As per the given condition :

we have;

$5(x+1)+x =83$

Using distributive property on LHS (i.e, $a\cdot(b+c)=a\cdot b+a\cdot c$ )

Then, we have

5x+5+x=83

Combine like terms;

6x+5=83

Subtract 5 from both the sides we get;

6x+5-5=83-5

Simplify:

6x=78

Divide both side by 6,

$\frac{6x}{6} =\frac{78}{6}$

Simplify:

x =13

Therefore, the original number x is, 13

8 0

3 years ago

the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

8 0

3 years ago