PLEASE help it would mean the world to me it would help so much please and thank you

The graph shows the functions f(x), p(x), and g(x):

Kruka [31]

Two functions have equal values where their graphs cross.

A) The solution to the pair of equations
.. y = p(x)
.. y = f(x)
will be where the graphs intersect, at (x, y) = (-3, -3).

B) We already know that (-3, -3) is one solution to y=f(x). The graph also appears to go through the point (0, 0).

C) p(x) = g(x) where their graphs cross, at x = -6. Both functions have the value 1 for that value of x.

8 0

3 years ago

Cade road 1 3/5th miles on Saturday and 1 3/4th on Sunday. how far did he ride on the two days?

krek1111 [17]

1.60 mi +1.75 mi = 3.35 mi = 3 7/20 mi

4 0

3 years ago

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$

Step-by-step explanation:

6 0

3 years ago

The maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4 parts per million (ppm). A consumer h

Elodia [21]

Answer:

Null hypothesis : $\mu \leq 0.4$

Alternative hypothesis: $\mu >0.4$

And for this case a type of error I for this case would be reject the null hypothesis that the population mean is lower or equal than 0.4 when actually is true.

A Type I error would occur if, in fact, μ ≤ 0.4 ppm, but the results of the sampling lead to the conclusion that μ > 0.4 ppm

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

Type II error, also known as a "false negative" is the error of not rejecting a null hypothesis when the alternative hypothesis is the true. Can be interpreted as the error of failing to accept an alternative hypothesis when we don't have enough statistical power

Solution to the problem

For this case we are trying to check the following hypothesis:

Null hypothesis : $\mu \leq 0.4$

Alternative hypothesis: $\mu >0.4$

And for this case a type of error I for this case would be reject the null hypothesis that the population mean is lower or equal than 0.4 when actually is true.

A Type I error would occur if, in fact, μ ≤ 0.4 ppm, but the results of the sampling lead to the conclusion that μ > 0.4 ppm

7 0

3 years ago

4 x plus 8 y equals 40, when y equals 0.8?

Over [174]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{x = 8.4}}}}}$