a) C(0.5) = 39, C(2) = 39, C(4) = 69
b) Answers in part (a) represents the values of C at x = x₀
c) C(x) is continuous at x = 2
C (x) = 39 for 0 ⩽ x ⩽ 2
Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:
C(0.5) = 39
Since x = 2 is in the range 0 ⩽ x ⩽ 2
C(2) = 39
Since x = 4 is in the range x > 2
C(4) = 39 + 15(x - 2)
C(4) = 39 + 15 (4 - 2)
C(4) = 39 + 15(2)
C(4) = 39 + 30
C(4) = 69
b) The answers in part A represents C(x). That is, the values of C at x = x₀
c) Is C(x) continuous at x = 2
C(2) = 39
Since 
, the function C(x) is continuous at x = 2
Learn more here: brainly.com/question/20710468
15x over 2 dont know how to do it on computer
4.2 is the answer of this question you are asking ✌️
Uhm, I'm pretty new to expanded form but I think it's something like:
(3 × 1/10) + (1 × 1/100) + (6 × 1/1000)
You can also write it as:
0.3 + 0.01 + 0.006
Let me know if you need working or anything!
You need to first set up the equation:
It would look like 90 divided by 360 multiplied by the given
circumference which is 72 cm.
So 90 / 360 x 72
Simply the fraction above, it will give us:
¼ x 72
So the answer would be 18 cm that is the length of DE (minor
arc)
