3 years ago

Determine the domain of the following graph:

Mathematics

1 answer:

Brut [27]3 years ago

3 0

Answer:

-10<x<6

Step-by-step explanation:

Find where x starts and where x ends

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BartSMP [9]

Answer:

∠EGF = 65°

Step-by-step explanation:

Since EF = EG the triangle is isosceles and the base angles are equal, that is

∠EGF = ∠GEF

∠EGF = $\frac{180-50}{2}$ = $\frac{130}{2}$ = 65°

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The graph of f(x) = 24x^2 + 63x +34/ 4x + 3 has an oblique asymptote at y =

g100num [7]

<em>Correct answer is C). 6X+11</em>

Step-by-step explanation:

The given function f(x)= $\frac{24x^{2} +63x + 34 }{4x+3}$

On simplying the function f(x),

f(x)= $\frac{6x(4x+3) -18x +63x + 34 }{4x+3}$

f(x)= $\frac{6x(4x+3) +45x + 34}{4x+3}$

f(x)= $\frac{6x(4x+3) +11(4x+3)+x-33 + 34 }{4x+3}$

f(x)= $\frac{6x(4x+3) +11(4x+3)+x+1}{4x+3}$

f(x)= $(6x+11)+\frac{(x+1)}{4x+3}$

From above equation

"(6x+11)" is Oblique asymptote and $\frac{(x+1)}{4x+3}$ is vertical asymptote

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