Ask question

Ask question

All categories

2 years ago

7

How minutes is in a clock

2 answers:

aksik [14]2 years ago

6 0

Answer:

720 Minutes

An analogue clock is split up evenly in two ways. Minutes are sixty equal parts and hours are 12 equal parts. That means that for every hour maker from 12 there are also five minute markers.

Hoped this helped!

Brainly, please?

alex41 [277]2 years ago

6 0

60 multiply by 12 so your answer is 720 minutes

You might be interested in

Silver's gym charges a $65 sign-up fee and $50 per month for their membership. Solar Fitness charges a $20 sign up fee and $55 p

alexandr1967 [171]

65+50x = 55x + 20
-50x -50
65=5x+20
- 20 - 20
55=5x
55/5= 5x/5
11=x
The solution represents that it 11 months will make both gyms the exact same price.

7 0

3 years ago

Is it possible to find a value of $x$ so that the value of the surface area (in square inches) is equal to the value of the volu

Annette [7]

The box has volume

11 in × 3 in × <em>x</em> in = 33<em>x</em> in³

and surface area

2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²

The volume and area have the same value if

33<em>x</em> = 66 + 28<em>x</em>

Solve this equation for <em>x</em> :

33<em>x</em> - 28<em>x</em> = 66

5<em>x</em> = 66

<em>x</em> = 66/5 = 13.2

7 0

3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago

2x-3 /(by) 3x+2 = -2/ (by) 3<br><br>Help ME PLLLEEAASSEE!

timurjin [86]

I forgot how to do this

5 0

2 years ago

Next → Post Test: The Pythagorean Theorem and Volume

Arte-miy333 [17]

X= 95°
Y= 133°
Z= 128°

7 0

2 years ago