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Alexeev081 [22]
3 years ago
14

2x-3 /(by) 3x+2 = -2/ (by) 3Help ME PLLLEEAASSEE!​

Mathematics
1 answer:
timurjin [86]3 years ago
5 0
I forgot how to do this
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Need some help here...
bekas [8.4K]
Cos Z = 32/40 => Z= cos-¹(32/40) =>

sin Z = sin (cos-¹(32/40)) = 3/5
4 0
3 years ago
How do I solve: 15 - w/4 = 28 (this is 2 step equations)
kenny6666 [7]
First we need to isolate the variable so we add 15 to both sides which is
w/4=43  then we need to multiply by 4 to both sides so its 4w=172
then divide by 4 which is 43 so the answer is w=43
8 0
3 years ago
Read 2 more answers
Compute the measures of center for both the boys and girls data. Describe their differences. Use the terms mean and median to ju
polet [3.4K]

Answer:boys: median=50, mean=46

Girls: median= 33, mean=34

Step-by-step explanation:

Mean is the average. Median is the middle number. Both groups had 10 scores. Boys ranged from 15-81. Girls from 0-75; their mean & median would be less because their scores are less.

6 0
4 years ago
Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}


\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
Read 2 more answers
john bought a full basket of mangoes when he got home he realised 12 out of the 20 mangoes he bought are bad what is the probabi
lara31 [8.8K]
12/20 mangoes are bad so 8/20 mangoes are good and to convert to a percentage we make the denominator 100.
To make 20 to 100 we times by 5 so we do the same to the numerator which is 8
So 8x5 = 40%
Give me brainliest answer plz
And hope it helps!
6 0
3 years ago
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