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Graph the line that represents the equation y=-2/3 x+1 helppp :(

Nady [450]

Step-by-step explanation:

Hi there!!

Here, your equation is y= -2/3 x +1

so, let's find coordinate. 

To find coordinate you must put the value of x.

so, when you keep value of x you will get,

x 0 3 6

y 1 -1 -3

Therefore, the coordinates are (0,1), (3,-1), (6,-3).

let me make you clear on using the value of x.

we generally put the value of variable (which is in right side) from a smaller digit like 0,1,2... or you may use 0,-1,-2... but they must be in eqaul interval such like i used the values in equal interval of 3 in above question.

I hope you got it...

if not you can ask me help..

now plot those points on graph, alright. 

best of luck...

4 0

3 years ago

Please help i do not understand.. ):

Paraphin [41]

Answer:

Your answer should be 18, that's what I got:)

Step-by-step explanation:

4 0

3 years ago

which function BEST expresses the linear relationship displayed by the scatter plot? A) y = 1.4x − 11.2 B) y = 0.7x − 10.8 C) y

ziro4ka [17]

Im not sure but correct answer is c)

3 0

3 years ago

Read 2 more answers

The perimeter of the base of a pentagonal prism is 25 inches and one of its lateral edges is 4 inches. The lateral area of the p

Nata [24]

Answer:

Lateral area=100 square inches

Step-by-step explanation:

It is given that the perimeter of the base of a pentagonal prism is 25 inches, therefore each sides of the pentagon will be of 5 inches.

Also, one of its lateral edge is 4 inches, therefore each lateral face has area which will be equal to= $5{\times}4$ = $20$ square inches.

Since, there are 5 lateral faces of the pentagonal prism, therefore the lateral area of the prism will be: $5{\times}20$

= $100$ square inches.

8 0

3 years ago

What is a decomposition reaction?

yaroslaw [1]

Answer:

11-6√3 = a -b√3

where a=11 and b =6

Step-by-step explanation:

Step(i):-

Given

$\frac{5+2\sqrt{3} }{7+4\sqrt{3} }$

Rationalize

= $\frac{5+2\sqrt{3} }{7+4\sqrt{3} } X \frac{7-4\sqrt{3} }{7-4\sqrt{3} }$

= $\frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{7^{2} -(4\sqrt{3})^{2} }$

= $\frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{49-16(3) }$

= $\frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{1 }$

Step(ii):-

Multiply

${(5+2\sqrt{3})(7-4\sqrt{3} ) }$

= 5 × 7 - 5×4√3 + 2√3 ×7 - 2√3 × 4√3

= 35 -20√3+ 14√3-8×3

= 35 - 6√3 -24

= 11-6√3

6 0

3 years ago