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ivolga24 [154]
3 years ago
9

A nurse starts at the hospital and travels to 5 appointments along a road. The positive numbers stand for going East. The negati

ve numbers stand for going West. Which expression gives the total number of miles he travels to get to these 5 appointments?
a.|6 + -9 + 3 1/2 + -6 1/4 + -3/4|
b.6 – 9 + 3 1/2 – 6 1/4 – 3/4
c.|6| + |-9| + |3 1/2| + |-6 1/4| + |-3/4|
d.|(+6) + (-9) + (3 1/2) + (-6 1/4) + (-3/4)|

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0
|6| + |-9| + |3 1/2| + |-6 1/4| + |-3/4|
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selena walks home to school each mm morning and back home each afternoon. altogether she walks 2/3 mile wach day. how far does s
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Answer:



One days trip of to school from home and back home from school is 2/3 of a mile. We want to know how far it is to school from her house.

To solve this, we simply need to take half of the total distance (2/3)

\frac{2}{3} / 2

Next, we need to turn the 2 into a fraction. Every whole number can be made into a fraction by putting it over 1.

\frac{2}{3} / \frac{2}{1}

Because we are dividing, we need to invert the second fraction and then multiply.

\frac{2}{3} * \frac {1}{2}

Next, we multiply the top of the first fraction by the top of the second and the bottom of the first fraction by the bottom of the second.

\frac{2}{6}

Once you reduce, you get:

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The next number in the series 13, 18, 16, 21, 19, is:  <br> 22<br> 23<br> 24<br> 25<br> 26 ...?
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3 years ago
Simplify each expression(OOF PLEASE HURRY FGHJHGFGHJ):
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allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD                 (Given)

\angle ADC\cong \angle ACD

m\angle ADC=m\angle ACD

According to the angle sum property, the sum of interior angles of a triangle is 180°.

m\angle ADC+m\angle ACD+m\angle DAC=180

m\angle ACD+m\angle ACD+44=180

2m\angle ACD=180-44

2m\angle ACD=136

Divide both sides by 2.

m\angle ACD=68

CE bisects ∠ACD.

m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}

m\angle ACE=m\angle DCE=\dfrac{68}{2}

m\angle ACE=m\angle DCE=34

Use angle sum property in triangle CDE,

m\angle CDE+m\angle DCE+m\angle DEC=180

68+34+m\angle DEC=180

68+34+m\angle DEC=180

102+m\angle DEC=180

Subtract 102 from both sides.

m\angle DEC=180-102

m\angle DEC=78

Therefore, the measure of angle DEC is 78°.

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