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Len [333]
3 years ago
14

Is 21q-7 equivalent to (3q-p)(7)

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0
They are equivalent ! both are 14
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-6n-20=-2n+4 (1-3n)<br> how do you solve it?
Leona [35]
6n−20=−2n+4(1−3n)

Simplify both sides of the equation.

−6n−20=−2n+4(1−3n)

−6n+−20=−2n+(4)(1)+(4)(−3n)(Distribute)

−6n+−20=−2n+4+−12n

−6n−20=(−2n+−12n)+(4)(Combine Like Terms)

−6n−20=−14n+4

−6n−20=−14n+4

Add 14n to both sides.

−6n−20+14n=−14n+4+14n

8n−20=4

Add 20 to both sides.

8n−20+20=4+20

8n=24

Divide both sides by 8.

8n/8 = 24/8

n=3

7 0
3 years ago
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Please answer 6 and 7
sleet_krkn [62]

Answer:

ok aaj SGD Hv the best of my friends in a couple days of a sudden in

8 0
3 years ago
What is the equation of the line that passes through the point (-3, 0) and has a slope of -1/3?​
ANTONII [103]

Answer:

Y=-1/3x-1

Step-by-step explanation:

Y-0=-1/3(x+3)

5 0
3 years ago
Does 17/3 = 68/12???
dimulka [17.4K]

Answer:

17/3 = 68/12

Step-by-step explanation:

17/3 =? 68/12

Get a common denominator of 12

17/3 * 4/4

68/12

They are equal so this is true

4 0
3 years ago
Read 2 more answers
Find each measurement indicated. Round your answers to the nearest tenth. Please show work. Part 1​
timama [110]

9514 1404 393

Answer:

  1. 33.0 m
  2. 26.1 mi
  3. 28.0 mi
  4. 33.0 mi

Step-by-step explanation:

In each of these Law of Sines problems, you are given side a and angles B and C and asked for side c (problems 1, 3, 4) or side b (problem 2). The solution is basically the same for each:

Find the missing angle. Find the side from ...

  c = a·sin(C)/sin(A)

__

1. angle A = 180°-89°-58° = 33°

  c = (18 m)sin(89°)/sin(33°) ≈ 33.0 m

__

2. angle C = 180°-13°-17° = 150°

  b = (58 mi)sin(13°)/sin(150°) ≈ 26.1 mi

__

3. angle A = 180°-61°-89° = 30°

  c = (16 mi)sin(61°)/sin(30°) = 28.0 mi

__

4. angle A = 180°-39°-127° = 14°

  c = (10 mi)sin(127°)/sin(14°) ≈ 33.0 mi

7 0
3 years ago
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