Answer:
2x-3y+z
Step-by-step explanation:
-2x-y-2z+4x-2y+3z
combine like terms
-2x+4x= 2x
-y-2y= -3y
-2z+3z= z
so..
2x-3y+z
The second quartile Q₂ is nothing but the Median.
This means that it median = 4.2
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
the length of the red line is 12
Answer:
y=-5x+16
Step-by-step explanation:
Plug in the slope and point coordinates into point-slope form (attached in image)
(y-6)=-5(x-2)
1) Distribute -5 to x and -2:
y-6=-5x+10
2) Add 6 to both sides:
y=-5x+16