Solve each equation by either substitution or addition method.

Mathematics

1 answer:

irina [24]3 years ago

6 0

Answer: (2,2), (4,2)

First, I subtracted 2y from both sides of the second equation. Then, I substituted -2y+6 in for x in the first equation (-2y+6)²+4y²=20. Then, I expanded 4y²-24y+16+4y²=20. Next, I combined like terms, and moved everything to one side 8y²-24y+16=0. Then, I factored out an 8, and then finished factoring 8(y-2)(y-1). This gives me my y-values, y=1,2. Next, I inserted each y-value into the second equation and got x=-2(1)+6 ---> x=4 (The first solution is (4,1). ) and x=-2(2)+6----->x=2 (The second solution is (2,2).

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Last autumn, julia noticed something interesting as she blew up spherical balloons for harris's birthday party. she calculated t

Vikki [24]

To find whether the volume would be doubled when the radius is,we can find the volume of the two balloons.

The formula of a sphere is:
$\frac{4}{3} \pi \: {r}^{3}$
Let's take 丌 as 3.14

The volume of the balloon with 4cm radius:
$\frac{4}{3}(3.14) \times {4}^{3} \\ = 4.18667 \times 64 \\ = 267.94688$

The volume of the balloon with 8cm radius:
$\frac{4}{3}(3.14) \times {8}^{3} \\ = 4.18667 \times 512 \\ = 2143.57504$
As we can see,
267.94668 × 2 = 535.89 ≠2145.56

Thus,she wouldn't discover that the volume is twice as big when the radius is doubled.

Hope it helps!

4 0

3 years ago

Read 2 more answers

What are all of these answers?

mina [271]

106

1573

53400

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hope this helps X D

5 0

3 years ago