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Illusion [34]
4 years ago
13

7. John's seafood restaurant is trying to estimate its profits. John has found that on average, each meal served costs the resta

urant $14.56 and takes in $17.12. John has also found that on average, each beverage served costs the restaurant $1.20 and takes in $5.40. If c customers order a meal, and half of those customers order a beverage, which of the following functions models the restaurant's total profit?
f(c) =17.12c -14.56c + 5.40(.5c) - 1.20(.5c)
f(c) = 17.12c - 14.56c + 5.4c - 1.20c
f(c)=14.56c - 17.12c + 1.20c - 5.40c14.56c - 17.12c + 12(.5c) - 5.40(.5c)
Mathematics
2 answers:
laiz [17]4 years ago
4 0

Answer:

f(c) =17.12c -14.56c + 5.40(.5c) - 1.20(.5c)

Step-by-step explanation:

Profit is the difference between revenue (17.12c +5.40(.5c)) and cost(14.56c+1.20(0.5c)). That difference is expressed by the function shown above.

ololo11 [35]4 years ago
4 0

Answer:

f(c) =17.12c -14.56c + 5.40(.5c) - 1.20(.5c)

Step-by-step explanation:

Let's build the f(c) function by steps.

There are c customers.

John has found that on average, each meal served costs the restaurant $14.56 and takes in $17.12.

So, the costs for the restaurant are negative, and what takes positive.

f(c) =17.12c -14.56c

Now the final part

John has also found that on average, each beverage served costs the restaurant $1.20 and takes in $5.40.

Half of these customers order a beverage, and this is why we multiply by 0.5.

So

f(c) =17.12c -14.56c + 5.40(.5c) - 1.20(.5c)

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Answer: The missing length is 40 m.

Step-by-step explanation:

30^2 + b^2 = 50^2

900 + b^2 = 2500

-900              -900

       b^2 = 1600

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3 years ago
celeste wants to have her hair cut and permed and also go to lunch. she knows she will need 59$. the perm cost twice as much as
miv72 [106K]
Let's first start off with an equation to represent Celeste's budget:
h + p + l = 59
Where:
'h' is the money in dollars that she needs to get her hair cut
'p' is the money in dollars that she needs to get her hair permed
'l' is the money in dollars that she needs for lunch

Now let's simplify this equation using the information that was given:
l = 5 *This must be true since it is told that she needs $5 for lunch
0.5p = h *This is because the perm costs twice as much as the hair cut

Our new/updated equation is:
0.5p + p + 5 = 59

This is much easier to solve, let's rearrange and solve for 'p':
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3 years ago
How to calculate confidence interval with standard deviation?
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Confidence interval of a standard deviation

A confidence interval can be computed for almost any value computed from a sample of data, including the standard deviation.

The SD of a sample is not the same as the SD of the population

It is straightforward to calculate the standard deviation from a sample of values. But how accurate is that standard deviation? Just by chance you may have happened to obtain data that are closely bunched together, making the SD low. Or you may have randomly obtained values that are far more scattered than the overall population, making the SD high. The SD of your sample does not equal, and may be quite far from, the SD of the population.

Confidence intervals are not just for means

Confidence intervals are most often computed for a mean. But the idea of a confidence interval is very general, and you can express the precision of any computed value as a 95% confidence interval (CI). Another example is a confidence interval of a best-fit value from regression, for example a confidence interval of a slope.

The 95% CI of the SD

<span>The sample SD is just a value you compute from a sample of data. It's not done often, but it is certainly possible to compute a CI for a SD. GraphPad Prism does not do this calculation, but a free GraphPad QuickCalc does.</span>

Interpreting the CI of the SD is straightforward. If you assume that your data were randomly and independently sampled from a Gaussian distribution, you can be 95% sure that the CI  contains the true population SD.

How wide is the CI of the SD? Of course the answer depends on sample size (n). With small samples, the interval is quite wide as shown in the table below.

n        95% CI of SD

2        0.45*SD to 31.9*SD

3        0.52*SD to 6.29*SD

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500        0.94*SD to 1.07*SD

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Example

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SD:        3.35

The sample standard deviation computed from the five values  is 3.35. But the true standard deviation of the population from which the values were sampled might be quite different. From the n=5 row of the table, the 95% confidence interval extends from 0.60 times the SD to 2.87 times the SD. Thus the 95% confidence interval ranges from  0.60*3.35 to 2.87*3.35,  from 2.01 to 9.62. When you compute a SD from only five values, the upper 95% confidence limit for the SD is almost five times the lower limit.

Most people are surprised that small samples define the SD so poorly. Random sampling can have a huge impact with small data sets, resulting in a calculated standard deviation quite far from the true population standard deviation.

Note that the confidence interval is not symmetrical around the computed SD. Why? Since the SD is always a positive number, the lower confidence limit can't be less than zero. This means that the upper confidence interval usually extends further above the sample SD than the lower limit extends below the sample SD. With small samples, this asymmetry is quite noticeable.

Computing the Ci of a SD with Excel

These Excel equations compute the confidence interval of a SD. n is sample size; alpha is 0.05 for 95% confidence, 0.01 for 99% confidence, etc.:

Lower limit: =SD*SQRT((n-1)/CHIINV((alpha/2), n-1))

<span>Upper limit: =SD*SQRT((n-1)/CHIINV(1-(alpha/2), n-1))
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3 years ago
HURRY!!!When are two triangles said to be in perspective?
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1. A
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2. B (13)
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Solnce55 [7]

Answer:

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Step-by-step explanation:

Suppose a set of data (2, 4, 6, 8, 10, 12)

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