Answer:
<h2>The length of the line segment VT is 13 units.</h2>
Step-by-step explanation:
We know that SU and VT are chords. If the intersect at point R, we can define the following proportion

Where

Replacing all these expressions, we have

Solving for
, we have

Now, notice that chord VT is form by the sum of RT and RV, so

Replacing the value of the variable

Therefore, the length of the line segment VT is 13 units.
PART A :OK so here is the table for the health inspector; all you are really doing is 7+7+7, and so on:
PART A: health inspector: 7,14,21,28,35,42,49,56,63,70,77,84..........
PART A:same thing for the fire inspector, except this time your adding 12+12+12, and so on:
PART A: fire inspector: 12,24,36,48,60,72,84,96.......
PART B: and to figure out what day they will both come is you have to find the LCM (least common multiple)
PART B: which in this case is Day 84
hopes this helps!!!!!
Answer:
Answer is below
Step-by-step explanation:
Yes, the graph would still be a function, but a different function than if the values were all different. This would cause two of the values to be the same and have no slope on the line. Before, the function was quadratic, but now it would be quadratic until the two values are equal.
Answer:
Remove all perfect squares from inside the square root. ... I think it's about eighth or ninth grade. ... so if you have the cube root of the square root of (x-5) =2, you get ((x-5)^(1/2))^1/3 = 2, power to power requires multiplication, so (x-5)^1/6 = 2, ...
Missing: 176 xy
Answer:
Radius is <u>2.8</u> Circumference is <u>17.584 or 17.6 Rounded to the nearest Tenths </u>
Step-by-step explanation:
1. Find circumference with the Formula <u>C=πd</u>
C=3.14 x 5.6
<u><em>C=17.584 or 17.6 Rounded to the nearest Tenths </em></u>
2. Radius is Always half of the Diameter.
5.6/2 = 2.8
<em><u>2.8 is your radius.</u></em>
3. If you want to check you work try the formula C=2πr to see if things checks out.
C=2 x 3.14 x 2.8
<u><em>C= 17.584 or 17.6 Rounded to the nearest Tenths </em></u>
<u><em /></u>
<u><em>Hope this Helps!</em></u>