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2 years ago

Is it A, B, or C? PLEASE HELP

Mathematics

2 answers:

Zanzabum2 years ago

6 0

Step-by-step explanation:

y = kx, where k is the constant of proportionality. (1)

Therefore y = x and line B depicts that.

andreev551 [17]2 years ago

6 0

Answer:

Step-by-step explanation:

It's B) because if you look at the slope of the line it goes through all the boxes points.

Another way to do it is take to points and do

m=y2-y1/x2-x1

Hope this helps!

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How do I know if an equation has one solution no solution or infinitely many solutions?

Lemur [1.5K]

Answer: If the equation ends with a false statement (ex: 0=3) then you know that there's no solution. If the equation ends with a true statement (ex: 2=2) then you know that there's infinitely many solutions or all real numbers.

Step-by-step explanation:

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2 years ago

Find the midpoint of segment JT when the coordinates are J(-3,18) and T(7,-10). Show all work

nignag [31]

Given two points (x₁,y₁) and (x₂,y₂), the midpoint of the segment will be:
( (x₁+x₂) / 2 , (y₁+y₂)/2 ).
In this case:
J(-3,18)
T(7,-10)

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3 years ago

Dilate the segment about the origin by a scale factor of 1 /2 What are the coordinates of B'? please help

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$