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REY [17]
3 years ago
5

How do I know if an equation has one solution no solution or infinitely many solutions?

Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0

Answer:  If the equation ends with a false statement (ex: 0=3) then you know that there's no solution. If the equation ends with a true statement (ex: 2=2) then you know that there's infinitely many solutions or all real numbers.

Step-by-step explanation:

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Brenda throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target clos
Masteriza [31]
Either way.  The probability of hitting the circle is:

P(C)=Area of circle divided by area of square

P(W)=(area of square minus area of circle divided by area of square

P(C)=(πr^2)/s^2

P(W)=(s^2-πr^2)/s^2

...

Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:

P(inside circle)=π/121  (≈0.0259  or 2.6%)

P(outside circel)=(121-π)/121  (≈0.9744 or 97.4%)
6 0
3 years ago
Use the relationships between the angles to find the value of x (please answer)
Varvara68 [4.7K]

Step-by-step explanation:

x + 15 \degree = 102 \degree \:  \\ (corresponding \:  \angle s) \\  \therefore \: x =  102 \degree -  15 \degree  \\  \huge \red { \boxed{\therefore \: x =  87 \degree}}

4 0
3 years ago
Conditional Distribution, Marginal Distribution, Joint Distribution. <br> What’s the difference?
lutik1710 [3]

Explanation:

Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.

Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

3 0
3 years ago
Nobody even helps on this app anymore it’s so annoying :(
son4ous [18]

Answer:

Sometimes it does take time but then yet again it can take weeks to get an answer depending on the question.

Step-by-step explanation:

<u><em>EXAMPLE: </em></u>Forenisc Science Questions that are usually under Biology. I saw someone that put up this answer and hasn't gotten a response in a whole week until I actually took the test and gave him/her the answer. It even happens to me. I have many answers that have not been answered but I get used to it :( Have a good one! :)    

8 0
3 years ago
Prove this identity using the product-to-sum identity for sin... sin^2 x=(1-cos(2x))/(2)
Simora [160]

Answer:

sin²x = (1 - cos2x)/2 ⇒ proved down

Step-by-step explanation:

∵ sin²x = (sinx)(sinx) ⇒ add and subtract (cosx)(cosx)

(sinx)(sinx) + (cosx)(cosx) - (cosx)(cosx)

∵ (cosx)(cosx) - (sinx)(sinx) = cos(x + x) = cos2x

∴ - cos2x + cos²x = -cos2x + (1 - sin²x)

∴ 1 - cos2x - sin²x = (1 - cos2x)/2 ⇒ equality of the two sides

∴ (1 - cos2x) - 1/2(1 - cos2x) = sin²x

∴ 1/2(1 - cos2x) = sin²x

∴ sin²x = (1 - cos2x)/2

4 0
4 years ago
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