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AysviL [449]
2 years ago
6

There are 160 boys and girls 0laying in a soccer tournament. 32 of them were where orange. What percent of the players are weari

ng orange?
Mathematics
1 answer:
Vesnalui [34]2 years ago
3 0

Answer:

20%

Step-by-step explanation:

You write 32/160 and simplify it. Then when your finished simplifying, you should get 1/5. 1/5, as you should all know, is also equivalent to 20%. Because 1/5 is 20% of 100.

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Celine and Arlene shared $400. Celine received $50 more than Arlene. How much money did Arlene receive?
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Answer:

Arlene had 175 and Celine had 225

Step-by-step explanation:

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2 years ago
Plot the line for the equation on thr graph. y-2=-2(x+4)​
julia-pushkina [17]

Answer:

see attached

Step-by-step explanation:

y-2=-2(x+4)​

y -2 = x(-2) + 4(-2)

y -2 = -2x - 8

y = -2x - 8 + 2

y = -2x - 6

When  x = 0, y = -6. Hence (0,-6) is a point on the line

when y = 0, x = -3. Hence (-3,0) is a point on the line.

Plot these 2 points and connect with a line (see attached)

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--> The managers want to know how many boxes of 12 cookies can
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Answer:

271 boxes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
3x - 5y = -16
murzikaleks [220]
X=3 y=5 hope this helped :)
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2 years ago
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