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liubo4ka [24]
3 years ago
6

1 Find the value of the expression 4a + 7 when a = 2

Mathematics
2 answers:
CaHeK987 [17]3 years ago
4 0

Answer:

15

Step-by-step explanation:

Gnom [1K]3 years ago
3 0
The answer is obviously 15.
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Solve for x given that <br><img src="https://tex.z-dn.net/?f=%20%7B64%7D%5E%7B2x%20-%201%7D%20%3D%20%20%7B32%7D%5E%7Bx%20%2B%201
marissa [1.9K]

Answer:

x = \frac{11}{7}

Step-by-step explanation:

note that 64 = 2^{6} and 32 = 2^{5} , thus

(2^{6}) ^{2x-1} = (2^{5}) ^{x+1} , that is

2^{6(2x-1)} = 2^{5(x+1)}

2^{12x-6} = 2^{5x+5}

Since the bases on both sides are equal, then equate the exponents

12x - 6 = 5x + 5 ( subtract 5x from both sides )

7x - 6 = 5 ( add 6 to both sides )

7x = 11 ( divide both sides by 7 )

x = \frac{11}{7}

8 0
4 years ago
Evaluate the numerical expression 2+(65+7) multiply 3=what
mina [271]
218 is the right answer
6 0
4 years ago
Read 2 more answers
There are 36 carpenters in a crew. On a certain day, 29 were present. What percent showed up for work? (round to the nearest ten
Liula [17]

Answer:

80.6%

Step-by-step explanation:

29/36 = about 0.8055556 = 80.55556% = about 80.6%

4 0
3 years ago
Read 2 more answers
Greg thinks of a number, multiplies it by 3, subtracts 5 and then multiplies by 2. His answer is 26. What number did Greg think
soldi70 [24.7K]

Answer:

x

3x

3x-5

2(3x-5)

so

2(3x-5)=26

3x-5=13

3x=18

x=6

he thought of 6

8 0
2 years ago
In a game of football outdoors on a cold day, a player will begin to feel exhausted after using approximately 8.0 × 105 J of int
Julli [10]

Answer:

a) How much work has he done = dW = 1.3 × 105 J

b) What is the magnitude of the heat that he has lost = dQ = -5.4 × 105 J

Step-by-step explanation:

  • From the first law of thermodynamics; dQ = dU + dW
  • dU = -8.0 × 105 J
  • dQ = -6.7 × 105 J

Hence, work done dW = dQ - dU

dW = -6.7 × 105 J - ( -8.0 × 105 J)

dW = 1.3 × 105 J is the work done by the player

  • for heat lost; from dQ = dW + dU
  • dU = -8.0 × 105 J and dW = 2.6 × 105 J
  • heat lost dQ = 2.6 × 105 J + ( -8.0 × 105 J)
  • dQ = -5.4 × 105 J
  • The negative is as a result of heat lost by the player

6 0
3 years ago
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