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Sonbull [250]
3 years ago
5

Why are online payments services necessary

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer:

Now a days, everyone is going digital. So, online payment services are a good option for paying bills for anything you want.

The major plus point is that you can pay your bills from home. You don't have to stand in long queues to pay your bills and also you do not have to worry about carrying cash with you.

With a simple click on the phone, you can pay even in thousands of dollars.

Semenov [28]3 years ago
5 0

In this digital age, online payment services are added services that will make bill payments easier. Online stores and businesses have cropped up and their market is worldwide. To facilitate easy exchange of goods and services, online payment services are offered. Online payment services benefit both the seller and the buyer. They buyer no longer need to go to a physical office to deposit his payment, all he has to do is lodge his debit or credit card to pay his bills or online purchases. Sellers also benefit from these services because he'll know that his buyers are not bogus and online payments are real-time transactions. Thus, making payment tracking easier for documentation purposes.


Can you mark me brainlest?


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Answer:

x = 16°

H = 46°

I = 55°

J = 39°

Step-by-step explanation:

Since the whole figure is 180°

Deduct 180 by the numbers mentioned above in order to find x.

180 - 2 - 9 - 9 = 160

3x + 4x + 3x = 10x

10 x = 160

x = 160 ÷ 10 = 16

Since we know what x is, we can find all the angles in the figure.

Angle at H = 3 x 16 - 2 = 46°

Angle at I = 4 x 16 - 9 = 55°

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The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin
tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

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Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950e^{0.45t}

a) rate of growth is

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b) Initial population of culture at t = 0

n(0) = 950e^{0.45(0)}

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