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ankoles [38]
3 years ago
10

Can somebody please help me I need help with this ASAP!! THANK YOU

Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

Perimeter: 72

Step-by-step explanation:

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2 years ago
I'm having trouble on ixl here is what I have to do
Sophie [7]

Answer:

6(9r-7)

Step-by-step explanation:

54r–42

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3 years ago
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The length of a rectangle is 8 inches longer than the width. If the area is 295 square inches, find the
sladkih [1.3K]

Answer:

L=21.6in and w=13.6

Step-by-step explanation:

If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8

Area is (width)(Length) = (width)(width+8)

W

----------

| |

| |

| | L = w+8

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-----------

A = (w+8)(w)

A = w2 + 8w = 295.

(Problem states that area is 295 sq in)

Need to solve this quadratic equation

w2 +8y - 295 = 0

Factor:

(w - 13.64) (w + 21.64) = 0

So

w - 13.64 = 0. or. w + 21.64= 0

Solve these and get

w = 13.64. or. w = -21.64

Only one that makes sense in real life is the poitive one.

So the dimensions are

Width = 13.64 inches

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7 0
3 years ago
Express the vector ModifyingAbove Upper P 1 Upper P 2 with right arrowP1P2 in the form Bold v equals v 1 Bold i plus v 2 Bold j
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3 0
3 years ago
Don’t understand this @ all
irina1246 [14]
Pair (3,11) should be removed because the domain x should never be repeated in a function.
Plz mark me as brainliest? Hope it helps.
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2 years ago
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