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sertanlavr [38]
3 years ago
15

Find the measure of the vertex angle in the figure below.

Mathematics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

∠m = 84º

Step-by-step explanation:

48 + 48 + x = 180

96 + x = 180

x = 84º

hope this helped!

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Perform the indicated operation <br><br>1. 1 3/5 + 2 4/5<br><br>2. 3/8 divide d by 2 2/5
valina [46]
1). 1 3/5 + 2 4/5 = 4 2/5 or 4.4

2). 3/8 ÷ 2 2/5 = 5/32 or 0.15625


Hope this helps
3 0
4 years ago
(20 POINTS!!!) which of the following terms describe the relationship between &lt;CFD and &lt;DFE? Chose all that apply. (2)
Sergio [31]

Answer:

A: adjacent angles: The angle ∠CFD & ∠DFE are directly  next to each other, making them <em>adjacent angles</em>.

B: Complementary angles: Note that m∠BFC measures at 90°. m∠BFE is a straight line, with 180°. This means that ∠BFE - ∠BFC = ∠DFE.

180 - 90 = 90 ∴ m∠DFE = 90°

~

6 0
4 years ago
Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for sev
kotykmax [81]

Answer:

105 frames

Step-by-step explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames.

7 0
4 years ago
Read 2 more answers
A rectangle has a height of k^2+3k 2 +3k, squared, plus, 3 and a width of k^2+7k 2 +7k, squared, plus, 7. Express the area of th
vlada-n [284]

Answer: k^4+10k^3+21k^2

Step-by-step explanation:

Given

Height of rectangle is h=k^2+3k

Width is w=k^2+7k

The area of the rectangle is given by the multiplication of the height and width

\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2

Thus, the area of the rectangle is k^4+10k^3+21k^2.

3 0
3 years ago
I BEG OF YOU HELPPPP Twice last​ month, Judy Carter rented a car in​ Fresno, California, and traveled around the Southwest on bu
sineoko [7]

Answer:

the daily fee =33 dollars

and the mileage charge.=0.35

Step-by-step explanation:

let d: be daily fee and m for mileage

cost of rental =(d*number of days)+ (m*number of mileage)

her first trip: 4d+440m=286

her second trip: 3d+190m=165.5

solve by addition and elimination

4d+440m=286 ⇒ multiply by 3 ⇒12d +1320m=(3)286

3d+190m=165.5⇒ multiply by 4⇒12d+190(4)m=4(165.5)

12d+1320m=858

12d+760m=662

subtract two equation to eliminate d

12d+1320m-12d-760m=858-662

560m=196

m=7/20=0.35 for on mileage

d: 4d+440m=286

4d=286-440(0.35)

d=(286-154)/4 33 dollars

8 0
4 years ago
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