Answer:
Step-by-step explanation:
To help you solve
Use the fact that (height of flagpole)/(length of shadow) = tan(angle of elevation).
Answer: 1. When you estimate, it is not an exact measurement. 3ft 8 in gets rounded to 4ft and 12 ft 3 in rounds to 12ft. now find the perimeter. P=2l+2w P= 2*12 +2*4 P=32feet
2. 3ft 8in = 3 8/12 or reduced to 3 2/3 12ft 3in = 12 3/12 or reduced to 12 1/4 The fractional part is referring to a fraction of a foot.
3. The perimeter of the room is P=2l+2w or P=2(12 1/4) + 2(3 2/3) p=24 1/2 + 7 1/3 P= 31 5/6 feet
4. The estimate and the actual are very close. They are 1/6 of a foot apart.
5a. Total baseboard 31 5/6ft - 2 1/4 ft = 29 7/12 feet needed.
5b. Take the total and divide it by 8ft = 29 7/12 divided by 8= 3.7 You are not buying a fraction of a board so you would need 4 boards.
When rearranged in the format “y = mx + b,” the correct equation would be 2y = -3x - 8.
Answer:
The anchor should be located at the midpoint between the 20m high and 60m high antennas.
Step-by-step explanation:
Let the length of cable for 20m high antenna be represented by x, and that for 60m high antenna be y.
The single length of cable required = x + y.
From the principle of geometry, if the cable is anchored at 200m from the 20m high antenna, it forms a right angled triangle. Applying the Pythagoras theorem,
x = 
= 199
Applying the same principle to the 60m high antenna gives,
y = 
= 191
The single length of cable required = 199+ 191
= 390m
Varying the point of location of the anchor between the two antennas causes an increase in the length of cable required.
The anchor should be located at the midpoint between the two antennas to achieve a minimum amount of cable.