Answer:
28 questions answered.
Step-by-step explanation:
40(2/5) is 16 questions.
40-16 is 24 questions left.
24(.5) is 12 questions.
16+12 gets you 28 questions.
Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
A.
<span>GCF(10; 2) = 2 /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/
B.
GCF(4; 6) = 2 /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>
C.
GCF(6; 12) = 6 /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>
D.
GCF(2; 24) = 2 <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>
</span>Answer: A, B and D.
Answer:
7
Step-by-step explanation:
