That’s easy it’s 18 because the 9x9=18 and there’s a 10s digit
<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal
to the x-coordinate of the vertex. </span>
<span>Note that a quadratic
equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at
h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>
Answer:
1/ 6^12
Step-by-step explanation:
f[x} = x ^ (-2x)
f(6) = 6 ^ (-2*6)
= 6 ^ -12
We know the negative exponent moves it to the denominator
= 1/ 6^12
Answer:
1)
angle 2WZX = angle ZYX ( Since all angles and sides of a rhombus are equal)
ZYX = 2 x 29.5
59
2)
4x - 10 =90 (since all angles of a rhombus intersect at 90°)
x=90+10/4
x=100/4
x=25
hope this helps
