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3 years ago

13

Mason spends $24 on hot dogs and buns for his graduation picnic. Hot dogs cost $3 per pack and buns cost $2 per packGraph the eq

uation that models this situation, given that represents packs of hot dogs and y represents packs of buns

1 answer:

iragen [17]3 years ago

5 0

Answer: i don’t know

Step-by-step explanation: because I don’t know

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What is the slope of the line

Mrrafil [7]

The slope of the line is undefined because the line doesnt pass through the origin. In order to calculate the slope the line must both be straight and pass through the origin.

4 0

3 years ago

Suppose a car's momentum is calculated to be 36000 . The mass of the car is 1,500 kg. What is the magnitude of the velocity of t

Ad libitum [116K]

Answer:

The magnitude of the velocity of the car is 24 m/s .

Step-by-step explanation:

Given : A car's momentum is calculated to be 36000 .

the mass of the car is 1500 kg.

To find: What is the magnitude of the velocity of the car.

Formula used:

Momentum =mass × velocity

Explanation:

We are given that momentum of the car =36000 .

Mass of the car = 1500 kg .

Plugging the given value in the above formula

Momentum =mass × velocity

36000 = 1500 × velocity

On dividing both side by 1500 we get ,

velocity = 24 meter/second

Therefore, The magnitude of the velocity of the car is 24 m/s .

4 0

3 years ago

An article reports "attendance dropped 7% this year, to 6854." What was the attendance before the drop? (Round your answer to th

Masja [62]

Answer:

7370

Step-by-step explanation:

Let x represent attendance before drop.

We have been given that an article reports attendance dropped 7% this year, to 6854. We are asked to find the attendance before the drop.

Since attendance dropped by 7%, this means that attendance after drop was 93% of x.

We can represent this information in an equation as:

$x-\frac{7}{100}x=6854$

$x-0.07x=6854$

$0.93x=6854$

$\frac{0.93x}{0.93}=\frac{6854}{0.93}$

$x=7369.89247$

$x\approx 7370$

Therefore, the attendance before drop was 7370.

4 0

4 years ago

Find the derivative of the following functions: a. f(x) = (x^3 + 5)^1/4 - 15e^x^3 b. f(x) = (x - 3)^2 (x - 5)/(x - 4)^2(x^2 + 3)

Darya [45]

Answer:

Step-by-step explanation:

Given function is

(a)F(x)= $\left ( x^{3}+5\right )^{0.25}-15e^{x^{3}}$

$F^{'}\left ( x\right )$ = $0.25\left ( x^{3}+5\right )^{-0.75}\frac{\mathrm{d} x^{3}}{\mathrm{d} x}-15e^{x^{3}}\frac{\mathrm{d} x^{3}}{\mathrm{d} x}$

$F^{'}\left ( x\right )=0.25\left ( x^{3}+5\right )^{-0.75}\times 3x^{2}-15e^{x^{3}}\times \left ( 3x^{2}\right )$

(b)F(x)= $\frac{\left ( x-3\right )^2\left ( x-5\right )}{\left ( x-4\right )^2\left ( x^{2}+3\right )^5}$

$F^{'}\left ( x\right )$ = $\frac{\left [ 2\left ( x-3\right )\right \left ( x-5\right )+\left ( x-3\right )^2]\left [ \left ( x-4\right )^2\left ( x^2+3\right )^5\right ]-\left [ 2\left ( x-4\right )^{3}\left ( x^2+3\right )^5+5\left ( x^2+3\right )^4\left ( 2x\right )\left ( x-4\right )^2\right ]\left [ \left ( x-3\right )^2\left ( x-5\right )\right ]}{\left [\left ( x-4\right )^2\left ( x^2+3\right )^5\right ]^2}$

6 0

4 years ago

Write two equivalent ratios of 7/10. 12/11. 3/2. 11/4. and 5/12.

TiliK225 [7]

7/10... 14/20, 28/40
12/11... 6/6.5, 24/22
3/2... 6/4, 12/8
11/4... 22/8, 33/16
5/12... 10/24, 20/48

3 0

3 years ago