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3 years ago

14

The floor of the cage measures 11 yardyard wide by 66 feetfeet long. One bag of shavings covers 55 square feetfeet. How many bag

s will HarperHarper have to buy to cover the floor of the cage? Explain.

1 answer:

bazaltina [42]3 years ago

5 0

Answer:

3 3/5 bags

Step-by-step explanation:

We have to find the surface area of the floor of the cage first.

The cage measures 1 yard wide by 6 feet long.

1 yard = 3 feet

The floor of the cage is rectangular, so, the surface area of the floor of the cage is therefore:

3 * 6 = 18 square feet

One bag of shavings covers 5 square feet.

To find the number of bags we need to cover the floor, we divide the surface area of the floor by the number of bags per square feet.

The number of bags needed for the floor of the cage is therefore :

18 / 5 = 3 3/5 bags

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zlopas [31]

Answer:

$x = 4$

Step-by-step explanation:

Let's solve:

$2(2−2x)=−3x$

Step 1: Simplify both sides of the equation.

$2(2−2x)=−3x \\ (2)(2)+(2)(−2x)=−3x(Distribute) \\ 4+−4x=−3x \\ −4x+4=−3x$

Step 2: Add 3x to both sides.

$−4x+4+3x=−3x+3x \\ −x+4=0$

Step 3: Subtract 4 from both sides.

$−x+4−4=0−4 \\ −x=−4$

Step 4: Divide both sides by -1.

$\frac{ - x}{ - 1} = \frac{ - 4}{ - 1}$

Therefore, the answer will be x = 4.

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2 years ago

You and two friends rent a hotel room that costs $30 so you both put in $10 each later that night the owner of the hotel realize

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The dollar didn't go anywhere! The question isn't correct because the money the bellhop stole is supposed to be subtracted, not added. So if we subtract $2 we have $25, and that's how much money the owner got, the men got $3 back and the bellboy got $2.

So the owner gets $25, the men get $3 and the bellboy gets $2, and that equals 30.

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3 years ago

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Multiply 32 times 6 7/24

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I think its 201.333333333

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How many different situations arise when five coins are thrown into the air?

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3 years ago

A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

<u>the answer Part a) is</u>

the speed is equal to $3.5\frac{m}{sec}$

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

<u>the answer Part b) is</u>

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

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therefore

<u>the answer Part c) is</u>

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

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