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Charra [1.4K]
3 years ago
6

Which equations are equal to this equation Select all that apply. 1/4(8x+56)=20

Mathematics
1 answer:
Zanzabum3 years ago
4 0
A and d are the answers
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it took 48 minutes to drive downtown. An app estimated it would be less than that. If the error was 20%, what was the apps estim
natulia [17]

Answer:

38.4

Step-by-step explanation:

it took 48 minutes and the app miss estimated by 9.6, which is 20% of 48. So subtract 9.6 from 48 and you will get 38.4

8 0
3 years ago
The equation having null set as its solution set is
KIM [24]

Answer:

  B) x = e^x

Step-by-step explanation:

The graphs of y = e^x and y = x never intersect, so the solution set will be the empty (null) set for ...

  x = e^x

_____

There is one intersection of y=x with cos(x) and with sin(x). There are an infinite number of solutions for x = tan(x).

4 0
3 years ago
PLZ HEEEEEEEELPPPPPPPP!!!!!!!!!
Elena L [17]
Y= ∛(-x) - 3
for x = -8 → y = ∛-(-8) - 3 ↔ y = 2-3 ↔y = -1
for x= 8 → y= ∛(-8) - 3 ↔ y = -2 -3 ↔ y = -5
Then  - 5≤ y≤ - 1
hence the range of y is {y|-5≤y≤-1}
5 0
3 years ago
Given the two sets, which statement is true?
monitta
I think it is 3 A but it is hard to know what the question is asking... but my logic is that 3 A is right because A = 1+2 = 3
6 0
3 years ago
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0
3 years ago
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