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lesya692 [45]
3 years ago
11

Luna is 12 blocks from school and walk towards the concert at an average speec of 2 blocks per minute. select the equation that

best represents luna's distance from school
A. d=2t+12
B. d=12+2
C. t=2d+12
D. t= 12d + 2​
Mathematics
1 answer:
irinina [24]3 years ago
5 0

Answer: I do not know

Step-by-step explanation:

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Question: What is the complementary angel of 31 degrees? <br><br> A.97<br> B.67<br> C.57 <br> D.87
Alona [7]
The complement of 31° is the angle that when added to 31° forms a right angle (90° ).
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3 years ago
y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence
sukhopar [10]

Let

\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots

Differentiating twice gives

\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots

\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0

\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0

Then the coefficients in the power series solution are governed by the recurrence relation,

\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

k=0 \implies n=0 \implies a_0 = a_0

k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}

k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}

k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}

It should be easy enough to see that

a_{n=2k} = \dfrac{a_0}{(2k)!}

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

k = 0 \implies n=1 \implies a_1 = a_1

k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}

k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}

k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}

so that

a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}

So, the overall series solution is

\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)

\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}

4 0
2 years ago
Alexus is ordering a large pizza for lunch. She has $15 dollars in all. A large pizza costs $9 and
exis [7]

Step-by-step explanation:

It would be

9+6 because 0.50 is a dollar so if u multiply by 6 and add the 9 the equation would be 9+6.......

don't forget get to rate me thx:)

4 0
3 years ago
How to do this problem
Maslowich

Answer:

1 tens   3 ones

Step-by-step explanation:

All you do is count the numbers in the place value chart.

Since 31-18=13, all you do is count 10+1+1+1=13.

3 0
3 years ago
$25 for a shirts $30 for a bag $40 get 10% ON WHAT YOU PURCHASE MARLIN BOUGHT 1 BAG 2 SHIRTS 2 PANTS
SSSSS [86.1K]

Answer: The question is incomplete.

Step-by-step explanation: I cannot give you the answer because i do not know the price of the pants.

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7 0
2 years ago
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