Answer:
d. d1− = 10, d1+ = 0
Explanation:
Given
3X1 + 4X2 +d1− − d1+ = 36
X1 = 6
X2 = 2
Required
Possible values of d1- and d1+
We have:
3X1 + 4X2 +d1− − d1+ = 36
Substitute values for X1 and X2
3 *6 + 4 * 2 + d1- - d1+ = 36
18 + 8 + d1- - d1+ = 36
Collect like terms
d1- - d1+ = 36 - 18 - 8
d1- - d1+ = 10
For the above equation to be true, the following inequality must be true
d1- > d1+
Hence,
(d) is correct
Because:
10 > 0
Answer:
Following are the program in the Python Programming Language.
#define function
def Transfer(S, T):
#set for loop
for i in range(len(S)):
#append in the list
T.append(S.pop())
#return the value of the list
return T
#set list type variable
S = ["a","b","c","d"]
#print the values of the list
print(S)
#set the list empty type variable
T=[]
#call the function
T = Transfer(S, T)
#print the value of T
print(T)
<u>Output:</u>
['a', 'b', 'c', 'd']
['d', 'c', 'b', 'a']
Explanation:
Here, we define the function "Transfer()" in which we pass two list type arguments "S" and "T".
- Set the for loop to append the values in the list.
- Then, we append the value of the variable "S" in the variable "T".
- Return the value of the list variable "T" and close the function.
- Then, set the list data type variable "S" and initialize the elements in it and print that variable.
- Finally, we set the empty list type variable "T" and store the return value of the function "Transfer()" in the variable "T" then, print the value of the variable "T".
