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3 years ago

2.6 + x = 10.4 What is x?

Mathematics

2 answers:

Mademuasel [1]3 years ago

4 0

Answer:

x = 7.8

Step-by-step explanation:

2.6 + x = 10.4

-2.6 -2.6

x = 7.8

You do the inverse operations to find out x

Tatiana [17]3 years ago

3 0

Answer:

x = 7.8

Step-by-step explanation:

$2.6+x=10.4\\\\2.6-2.6+x=10.4-2.6\\\\\boxed{x=7.8}$

Hope this helps.

You might be interested in

(a-b)^2/(1/a-1/b) simplify

leva [86]

Final result :

(b - a) • (a2 + ab + b2)

————————————————————————

a2b3

Step by step solution :

Step 1 :

Simplify —

Equation at the end of step 1 :

1 1 1

————-———— ÷ (—•b)

(a2) (b2) a

Step 2 :

Simplify ——

Equation at the end of step 2 :

1 1 b

———— - —— ÷ —

(a2) b2 a

Step 3 :

1 b

Divide —— by —

b2 a

3.1 Dividing fractions

To divide fractions, write the divison as multiplication by the reciprocal of the divisor :

1 b 1 a

—— ÷ — = —— • —

b2 a b2 b

Multiplying exponential expressions :

3.2 b2 multiplied by b1 = b(2 + 1) = b3

Equation at the end of step 3 :

1 a

———— - ——

(a2) b3

Step 4 :

Simplify ——

Equation at the end of step 4 :

1 a

—— - ——

a2 b3

Step 5 :

Calculating the Least Common Multiple :

5.1 Find the Least Common Multiple

The left denominator is : a2

The right denominator is : b3

Number of times each Algebraic Factor

appears in the factorization of:

Algebraic

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

a 2 0 2

b 0 3 3

Least Common Multiple:

a2b3

Calculating Multipliers :

5.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = b3

Right_M = L.C.M / R_Deno = a2

Making Equivalent Fractions :

5.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. b3

—————————————————— = ————

L.C.M a2b3

R. Mult. • R. Num. a • a2

—————————————————— = ——————

L.C.M a2b3

Adding fractions that have a common denominator :

5.4 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

b3 - (a • a2) b3 - a3

————————————— = ———————

a2b3 a2b3

Trying to factor as a Difference of Cubes:

5.5 Factoring: b3 - a3

Theory : A difference of two perfect cubes, a3 - b3 can be factored into

(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =

a3+a2b+ab2-ba2-b2a-b3 =

a3+(a2b-ba2)+(ab2-b2a)-b3 =

a3+0+0+b3 =

a3+b3

Check : b3 is the cube of b1

Check : a3 is the cube of a1

Factorization is :

(b - a) • (b2 + ab + a2)

Trying to factor a multi variable polynomial :

5.6 Factoring b2 + ab + a2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :

(b - a) • (a2 + ab + b2)

————————————————————————

a2b3

4 0

4 years ago

Assume that 140 surveys are completed. Of those surveyed, 71 responded positively to effectiveness, 60 responded positively to s

liraira [26]

Answer:

Step-by-step explanation:

Let n(T) denotes total surveys done i.e. n(T)=140

Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71

Let n(B) be the no. of side effects i.e.n(B) =60

Let n(C) be the no. of responses to cost i.e. n(C)= 65

33 responded positively to both effectiveness and side effects

So, n(A∩B)=33

31 to effectiveness and cost

n(A∩C)=31

28 to side effects and cost

n(B∩C)=28

21 to none of the items

So, n(A∪B∪C)=140-21 = 119

we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)

Formula:

n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)

119=71+60+65-33-31-28+ n(A∪B∪C)

119=104+ n(A∪B∪C)

119-104= n(A∪B∪C)

15= n(A∪B∪C)

Hence 15 responded positively to all three

7 0

3 years ago

An experiment consists of ranomly drawing three cards in succession without replacement from a standard deck of 52 cards. Let A

nadya68 [22]

Answer:

0.0045248 ;

0.1312218 ;

0.0001809 ;

0.1659729

Step-by-step explanation:

Number of Kings in deck = 4

Total number of cards in deck = 52

Picking without replacement :

A = King on first draw :

P(A) = 4 / 52

A = King on 2nd draw :

P(B) = 3 / 51

A = King on 3rd draw :

P(C) = 2 / 50

1.) P(A n B) = P(A) * P(B)

P(A n B) = 4/52 * 3/51 = 12 / 2652 = 0.0045248

2.) P(A u B) = P(A) + P(B) - P(AnB)

P(AuB) = 4/52 + 3/51 - 0.0045248 = 0.1312218

3.) P(A ∩ B ∩ C) = P(A) * P(B) * P(C)

P(A ∩ B ∩ C) = 4/52 * 3/51 * 2/50 = 0.0001809

4.) P(A U B U C) =

P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) - P(AnBnC)

P(AnC) = P(A) * P(C) = 4/52 * 2/50 = 0.0030769

P(BnC) = P(B) * P(C) = 3/51 * 2/50 = 0.0023529

4/52 + 3/51 + 2/50 - 0.0045248 - 0.0030769 - 0.0023529 + 0.0001809 = 0.1659729

6 0

3 years ago

Can you help me guys on this question?

Travka [436]

Answer:

The missing height is approximately 78.8011 feet.

Step-by-step explanation:

To solve for the height of the kite, you need to use a trigonometry function called sine. Sine - or sin when used to calculate - is most commonly used for right triangles, and the sine of a right triangle angle is equivalent to the side opposite (or the only side of the right triangle that does not help create that angle) of the angle divided by the hypotenuse of the right triangle. So you can now create the following function to solve the height: sin(52°) = $\frac{x}{100}$ where x represents the unknown height of the kite. From there, you can get that $x = 100*sin($ 52° $)$ , which equals approximately 78.8011 feet. Since there isn't a specific decimal place to round to, I rounded the answer to four decimals. If your teacher asks you to round to a specific place value, use 78.8011 to get your simplified answer.

6 0

3 years ago

Expansion of (4x+1)(2x2-2)

kvv77 [185]

8x3 - 8x + 2x2 - 2
8x3 + 2x2 - 8x - 2

7 0

3 years ago

Read 2 more answers