Answer:
h= -128t
Step-by-step explanation:
- 16t+128t
-256t + 128
Step-by-step explanation:
Perimeter of figure
![= 5 + 2 \times 7 + \pi \: r \\ = 5 + 14 + 3.14 \times 5 \\ = 19 + 15.70 \\ = 34.70 \: in \:](https://tex.z-dn.net/?f=%20%3D%205%20%2B%202%20%5Ctimes%207%20%2B%20%20%5Cpi%20%5C%3A%20r%20%5C%5C%20%20%20%3D%205%20%2B%2014%20%2B%203.14%20%5Ctimes%205%20%5C%5C%20%20%3D%2019%20%2B%2015.70%20%5C%5C%20%20%3D%2034.70%20%5C%3A%20in%20%5C%3A%20)
The
![100(1-\alpha)\%](https://tex.z-dn.net/?f=100%281-%5Calpha%29%5C%25)
confidence interval of a standard deviation is given by:
![\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7B%28n-1%29s%5E2%7D%7B%5Cchi%5E2_%7B1-%20%5Cfrac%7B%5Calpha%7D%7B2%7D%20%7D%20%7D%7D%20%5Cleq%5Csigma%5Cleq%5Csqrt%7B%20%5Cfrac%7B%28n-1%29s%5E2%7D%7B%5Cchi%5E2_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%20%7D%20%7D%7D)
Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,
![\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493](https://tex.z-dn.net/?f=%5Cchi%5E2_%7B1-%20%5Cfrac%7B%5Calpha%7D%7B2%7D%20%7D%3D43.773%20%5C%5C%20%20%5C%5C%20%5Cchi%5E2_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%20%7D%3D18.493)
Therefore, the 90% confidence interval for the standard deviation is given by
525/538=0.975 (round up Bc of the 5)
98% of the votes
Answer:
2,520
Step-by-step explanation:
The number of possible arrangements of officers patrolling the streets is the combination of choosing 5 officers out of 10 (₁₀C₅). After choosing the patrolling officers, the number of arrangements for the officers working full time at the station is given by the combination of choosing 2 officers out of the 5 remaining (₅C₂). The remaining officers should be on reserve at the station (₃C₃). The total number of arrangements is:
![N = _{10}C_5*_5C_2*_3C_3\\N=\frac{10!}{(10-5)!5!} *\frac{5!}{(5-2)!2!}*\frac{3!}{(3-3)!3!} \\N=2,520](https://tex.z-dn.net/?f=N%20%3D%20_%7B10%7DC_5%2A_5C_2%2A_3C_3%5C%5CN%3D%5Cfrac%7B10%21%7D%7B%2810-5%29%215%21%7D%20%2A%5Cfrac%7B5%21%7D%7B%285-2%29%212%21%7D%2A%5Cfrac%7B3%21%7D%7B%283-3%29%213%21%7D%20%5C%5CN%3D2%2C520)
There are 2,520 possible divisions.