Given that:
[{1(1/5)−(2/5)⋅(−3/4)3}]÷(−9)
= [{(5+1)/5 - (2/5).(-3/4)3}]÷(-9)
= [{(6/5) - (2/5).(-3/4)3}]÷(-9)
= [{(6/5) - (2/5).(-3/4)3}]÷(-9)
= [{(6/5) - (2/5).(-3*3)/4}]÷(-9)
= [{(6/5) - (2/5) . (-9/4)}]÷(-9)
= [{(6/5) - (2/5) × (-9/4)}]÷(-9)
= [{{6/5) - {{2*(-9)}/{5*4}]}]÷(-9)
= [{(6/5) - {-9/(5*2)}}]÷(-9)
= [{(6/5) - (-9/10)}]÷(-9)
Take the LCM of 5 & 10 is 10.
= [{(6*2 + 9*1)/10}]÷(-9)
= [{(12+9)/10}]÷(-9)
= [{-(21/10)}]÷(-9)
= -(21/10) ÷ (-9)/1
= -(21/10) × (1/9)
= {(-21*1)/(10*9)]
= {-21/90)
= {(-21÷3)/(90÷3)}
= -9/30
= {(-9÷3)/(30÷3)}
= (-3/10) = -3/10 Ans.
