Answer:
<x = 31°
Step-by-step explanation:
m<BCA = m<GCJ (vertical angles)
m<BCA = 59° (substitution)
Since line KL is perpendicular to line FG, the angle formed at point B is 90°.
Therefore, m<ABC = 90°
m<BAC + m<ABC + m<BCA = 180° (sum of triangle)
m<BAC + 90° + 59° = 180° (Substitution)
m<BAC + 149° = 180°
m<BAC = 180° - 149°
m<BAC = 31°
<x = <BAC (vertical angles)
m<x = 31° (substitution)
Answer:
c
Step-by-step explanation:
25% = 15$ so 15+15+15+15=60
Answer:
The sum of arithmetic series is - 2119 .
Step-by-step explanation:
Given as :
The first term of series = a = - 94
The 26th term of series = = - 69
The number of term = n = 26
Now, Let The sum of arithmetic series =
So, = × (First term + Last term)
Or, = × (a + )
or, = 13 × ( - 94 - 69 )
or, = 13 × ( - 163 )
or, = - 2119
or, the sum of 26 arithmetic series = = - 2119
Hence The sum of arithmetic series is - 2119 . Answer
Answer:
D. 1.5
Step-by-step explanation:
One basic property you need to keep in mind while solving theses type of questions is as follows :
<u>The length of tangents from an external point on a circle are equal</u>. For simplicity a figure illustrating this property is attached.
- Length of RS = 6 ; Length of AS = RS - AR = 6-x
Consider S as external point and tangents as SA and SB, so SB=SA=6-x
- Length of ST = 9 ; Length of TB = ST - SB = 9 - (6-x) = 3+x
Consider T as external point and tangents as TB and TC, so TC=TB=3+x
- Length of TU = 7 ; Length of UC = TU - TC = 7 - (3+x) = 4-x
Consider U as external point and tangents as UC and UD, so UD=UC=4-x
- Length of UV = 15 ; Length of VD = UV - UD = 15 - (4-x) = 11+x
Consider V as external point and tangents as VD and VE, so VE=VD=11+x
- Length of VR = 14 ; Length of RE = VR - VE = 14 - (11+x) = 3-x
Now, Consider R as external point and tangents as RA and RE, so
RA = RE
x = 3 - x
2x = 3
x =
x = 1.5
Good evening ,
Answer:
(x - 6 + i)(x - 6 - i) = x² - 12x + 37
Step-by-step explanation:
(x - 6 + i)(x - 6 - i) = [(x - 6) + i]×[(x - 6) - i] = (x-6)² - i² = (x-6)² + 1 = x² - 12x + 37 .
:)