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mixas84 [53]
3 years ago
14

Solve each equation. List any restrictions. Check your solutions. 12/x+11=17

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
6 0
12+11x=17x11x+12=17x
(both sides of the equation)
11x+12−17x=17x−17x
(Subtract 17x from both sides)
−6x+12=0−6x+12−12=0−12
(Subtract 12 from both sides)
−6x=−12−6x−6=−12−6
(Divide both sides by -6)
x=2
Check answers. (Plug them in to make sure they work.)
x=2
(Works in original equation)

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Use Socratic by google
6 0
3 years ago
in a certain game, a fair die is rolled and a player gains 20 points if the die shows a 6. if the die does not show a 6, the pla
BaLLatris [955]

The expected gain or loss is an illustration of mean and expected values.

The expected total gain is 83 points

The given parameters are:

  • Addition of 20 points for rolling a 6
  • Removal of 3 points for not rolling a 6

The probability of rolling a 6 in a fair die is 1/6.

The probability of not rolling a 6 in a fair die is 5/6.

So, the expected gain in each game is:

\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}

\mathbf{E(x) = \frac{20}6 -  \frac{15}6}

Take LCM

\mathbf{E(x) = \frac{5}6}

\mathbf{E(x) = 0.83}

The number of games is 100.

So, the expected gain is:

\mathbf{Gain = 100 \times 0.83}

\mathbf{Gain = 83}

Hence, the expected total gain is 83 points

Read more about expected value at:

brainly.com/question/13499496

5 0
3 years ago
A population has a mean muequals160 and a standard deviation sigmaequals20. Find the mean and standard deviation of the sampling
hoa [83]

Answer:

Mean 160

Standard deviation 2.63

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 160, \sigma = 20

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.

Mean 160

Standard deviation s = \frac{20}{\sqrt{58}} = 2.63

6 0
4 years ago
April measured her bed and made a scale drawing. The scale of the drawing was 1
ser-zykov [4K]

Answer:

60 inches

Step-by-step explanation:

Given data

We have the scale of the drawing as

1cm= 6 inches

Now if 1 cm is equivalent to 6inches

then 10cm will be x inches

Cross multiply we have

x*1= 10*6

x= 60 inches

Hence the length of the actual bed is 60inches

8 0
3 years ago
create a histogram with five intervals from this data set: 21, 37, 56, 87, 32, 45, 77, 71, 65, 67, 21, 34 step 1: find the minim
schepotkina [342]

Answer:

Step-by-step explanation:

Step 1: Minimum= 21     Maximum= 87

Step 2: Range minimum= 20

Step 3: Range maximum= 90

Step 4: Range 90-20= 70

5 0
4 years ago
Read 2 more answers
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