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Anvisha [2.4K]
3 years ago
14

Provide the missing reasons for the proof given <C <E prove: ∆ABC ~DBE

Mathematics
2 answers:
Softa [21]3 years ago
6 0

For two triangles to be similar.

The ratio of their sides must be in proportion.(SSS)

Any two angles of one triangle must be equal to two angles of another triangle. (AA)

Ratio of two sides must be in proportion and the included angles must be congruent.

Here in the figure it is given that

<C = <E

Also

<ABC = <DBE as they are vertical angles.

So by AA

ΔABC ~ ΔDBE.

alisha [4.7K]3 years ago
3 0
Do you have a picture of the proof? No one can answer it without seeing the shape and angles and such.
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Nuetrik [128]

The number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is  924, 000 ways

<h3>How to determine the combination</h3>

Note that the formula for combination is given as;

Combination = \frac{n!}{r!(n-r)!}

From the information we have that;

There are 28 questions in the pool

The test should have a total of 10 questions;

6 difficult , 10 average and 12 easy questions

We are asked to determine the combination of;

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4 average questions

3 easy questions

6C3 = \frac{6!}{3!(6-3)!}

6C3 = \frac{720}{36}

6C3 = 20

10C4 = \frac{10!}{4!(10-4)!}

10C4 = \frac{3628800}{17280}

10C4 = 210

12C4 = \frac{12!}{4!(12-4)!}

12C4 = 220

The number of ways of constructing the questions is

= 20 × 210 × 220

= 924, 000 ways

Thus, the number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is  924, 000 ways

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brainly.com/question/4658834

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7 0
2 years ago
140% as a fraction or whole number
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4 0
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Answer:

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