Question

Provide the missing reasons for the proof given <C <E prove: ∆ABC ~DBE

Answer 1

For two triangles to be similar.

The ratio of their sides must be in proportion.(SSS)

Any two angles of one triangle must be equal to two angles of another triangle. (AA)

Ratio of two sides must be in proportion and the included angles must be congruent.

Here in the figure it is given that

<C = <E

Also

<ABC = <DBE as they are vertical angles.

So by AA

ΔABC ~ ΔDBE.

Answer 2

Do you have a picture of the proof? No one can answer it without seeing the shape and angles and such.