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3 years ago

Helppppo plss zoom in on picture if u need but i need answer soon

Mathematics

2 answers:

castortr0y [4]3 years ago

7 0

The person above me is correct

nekit [7.7K]3 years ago

5 0

Answer: third number line

Step-by-step explanation:

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3 years ago

What is the index in the expression<br> 2<br> 2?

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The number of minutes taken for a chemical reaction if f(t,x). it depends on the temperature t degrees celcius, and the quantity

tatiyna

Hello,

Just for the fun, it's been a long time for that.

$f(30,5)=50\\

f(t+3,x)=f(t,x)-5\ ==\textgreater \dfrac{f(t+3,x)-f(t,x)}{3}= -\frac{5}{3} \\

f(t,x+2)=f(t,x)-3\ ==\textgreater\dfrac{f(t,x+2)-f(t,x)}{2}= -\frac{3}{2} \\

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f(33,4)\approx f(30,5)- \dfrac{5}{3} *3-\dfrac{3}{2}*(-1)= 50- 5+1.5=46.5\\


$

6 0

3 years ago

Please help me !!

AnnyKZ [126]

1. Exponential
2000 times 2= 4000 (60)
4000 times 2= 8000 (120)
8000 times 2= 16000 (180)
16000 times 2= 32000 (240)
2. pull a 2x out of everything
answer is b

3 0

3 years ago

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Suppose that the national average for the math portion of the College Board's SAT is 510. The College Board periodically rescale

Marta_Voda [28]

Answer:

a) 0.1587 b) 0.023 c) 0.1587 d) 1.15 e)-0.95

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 510

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score greater than 610)

P(x > 610)

$P( x > 610) = P( z > \displaystyle\frac{610 - 510}{100}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 610) = 1 - 0.8413 = 0.1587 = 15.87\%$

b) P(score greater than 710)

$P(x > 710) = P(z > \displaystyle\frac{710-510}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)$

Calculating the value from the standard normal table we have,

$1 - 0.977 = 0.023 = 2.3\%\\P( x > 710) = 2.3\%$

c)P(score between 410 and 510)

$P(410 \leq x \leq 510) = P(\displaystyle\frac{410 - 510}{100} \leq z \leq \displaystyle\frac{510-510}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%$

$P(410 \leq x \leq 510) = 34.1\%$

d) x = 625

$z_{score} = \displaystyle\frac{625 - 510}{100} = \displaystyle\frac{115}{100} = 1.15$

e) x = 415

$z_{score} = \displaystyle\frac{415 - 510}{100} = \displaystyle\frac{-95}{100} = -0.95$

8 0

3 years ago