The answer is B. On the off chance that a point is on the opposite bisector of a portion, at that point, it is equidistant from the endpoints of the fragment. Opposite of the Perpendicular Bisector Theorem: If a point is equidistant from the endpoints of the fragment, at that point it is on the opposite bisector of the portion.
13) BCA = 90*
CAB = tan^-1 (10/13)
= 37.57*
ABC = tan^-1 (13/10)
= 52.43*
14) ACB = 90*
CBA = tan^-1 (2/3)
= 33.69*
BAC = tan^-1 (3/2)
= 56.31*
Tthe answer is 3. 3=S 4 x 3 + 1 = 13
x^2-x-72 =0
find 2 numbers when multiplied = -72 and when added = 1
the zeros are 9 and -8
2a is 2 x a
Substitute a =5
2 x 5 =10
Now we have:
10^2-c
Substitute c = 10
(2 - 10 = - 8)
So,it's now 10^ - 8 (10 to the power of - 8)
Ans: 10^ - 8 (or 1 x 10^ -8)
Hope this helps!
