All categories

3 years ago

Find and type in the Constant of proportionality for this graph, AND write the equation in the form of y=kx.

Mathematics

1 answer:

stepladder [879]3 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

Question 5 (12 points)

Dima020 [189]

Answer:

see attached for diagram

a) √13

b) √29

c) 4

Step-by-step explanation:

Equation of the circle: $(x + 1)^2 + (y - 3)^2 = 16$

⇒ center = (-1, 3)

⇒ radius = √16 = 4

Distance between 2 points formula:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

a) let (-1, 3) = $(x_1,y_1)$

let (2, 1) = $(x_2, y_2)$

$\implies \sqrt{(2+1)^2+(1-3)^2} =\sqrt{13}$

b) let (-1, 3) = $(x_1,y_1)$

let (4, 1) = $(x_2, y_2)$

$\implies \sqrt{(4+1)^2+(1-3)^2} =\sqrt{29}$

c) let (-1, 3) = $(x_1,y_1)$

let (3, 3) = $(x_2, y_2)$

$\implies \sqrt{(3+1)^2+(3-3)^2} =4$

4 0

3 years ago

Read 2 more answers

3(y+7)+8y plz be spacific and answer correctly, im counting on you. :)

Galina-37 [17]

Answer:

11y + 21

Step-by-step explanation:

mutipily 3 by y + 7 bc 3 is right outside of the parentheis which means to mutipily. Then u get 3y +21 +8y. then simpilfy

7 0

3 years ago

2(4+2x)≥5x+5 solve inequality

valkas [14]

Answer:

x ≤ 3

Step-by-step explanation:

2(4+2x)≥5x+5

8+4x≥5x+5

4x-5x≥5-8

-x≥-3

x ≤ 3

6 0

3 years ago

Read 2 more answers

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

Please solve and please make sure your correct

Mazyrski [523]

Answer:

(a) The ones that are equivalent to the given fraction are: $\frac{2}{-9}$ and $-\frac{2}{9}$

(b) The one that is equivalent to the given fraction is: $\frac{-8}{-5}$

3 0

2 years ago