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masya89 [10]
2 years ago
7

During a sale, fidget spinners 1/4 off the regular price. If a spinner regularly costs 5.90, what is the sale price

Mathematics
1 answer:
garik1379 [7]2 years ago
8 0

price - (1/4)×price = price×(1 - 1/4) = (3/4)×price

... = (3/4)×5.90 = 4.425 ≈ 4.43 . . . . . sale price

_____

The sale price could be 4.42 if the discount is rounded up, rather than the price being rounded up. If you first compute the discount as (1/4)×5.90 = 1.475 ≈ 1.48, then the half-penny goes to the customer, not the shop-keeper.

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4/1 is the same as 4.

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Which equation will create a system of equations with infinitely many solutions?
SashulF [63]

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A and D

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6 0
3 years ago
During his vacation, Dalyn rents a small boat from a rental service that charges a flat fee of $60 plus $20 per hour (including
boyakko [2]

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2 years ago
Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex
I am Lyosha [343]

Answer:

z = -1.53 --- test statistic

p = 0.1260 --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

n_1 = 80     \bar x_1= 104   \sigma_1 = 8.4

n_2 = 70    \bar x_2 = 106    \sigma_2 = 7.6

H_o: \mu_1 - \mu_2 = 0 --- Null hypothesis

H_a: \mu_1 - \mu_2 \ne 0 ---- Alternate hypothesis

\alpha = 0.05

Solving (a): The test statistic

This is calculated as:

z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}

So, we have:

z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}

z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}

z = \frac{-2}{\sqrt{0.8820 + 0.8251}}

z = \frac{-2}{\sqrt{1.7071}}

z = \frac{-2}{1.3066}

z = -1.53

Solving (b): The p value

This is calculated as:

p = 2 * P(Z < z)

So, we have:

p = 2 * P(Z < -1.53)

Look up the z probability in the z score table. So, the expression becomes

p = 2 * 0.0630

p = 0.1260

Solving (c): With \alpha = 0.05, what is the conclusion based on the p value

We have:

\alpha = 0.05

In (b), we have:

p = 0.1260

By comparison:

p > \alpha

i.e.

0.1260 > 0.05

So, we fail to reject the null hypothesis.

4 0
2 years ago
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