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expeople1 [14]
3 years ago
9

Guided Practice

Mathematics
2 answers:
levacccp [35]3 years ago
7 0
I’m pretty sure the answer is A
GalinKa [24]3 years ago
3 0

Answer:

Step-by-step explanation:

Simplify the expression.

Exact Form:

−

73

11

Decimal Form:

−

6.

¯¯¯¯

63

Mixed Number Form:

−

6

7

11

−

40

11

−

3

Move the negative in front of the fraction.

−

40

11

−

3

To write  

−

3

as a fraction with a common denominator, multiply by  

11

11

.

−

40

11

−

3

⋅

11

11

Combine  

−

3

and  

11

11

.

−

40

11

+

−

3

⋅

11

11

Combine the numerators over the common denominator.

−

40

−

3

⋅

11

11

Simplify the numerator.

Tap for more steps...

−

73

11

Move the negative in front of the fraction.

−

73

11

The result can be shown in multiple forms.

Exact Form:

−

73

11

Decimal Form:

−

6.

¯¯¯¯

63

Mixed Number Form:

−

6

7

11

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Rudiy27

Answer:

The two coordinates should be (6, 3) and (10, 4).

Step-by-step explanation:

rise / run

y-value of the 2nd coordinate = 3 + 1 = 4

x-value of the 2nd coordinate = 6 + 4 = 10

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Based on What you learned about economics of organic produce, explain why buying organic food is so expensive
Elis [28]

Answer:(:

Step-by-step explanation:

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The notation __1____ reads the probability of Event B given that Event A has occurred. If Events A and B are independent, then t
telo118 [61]

P(B|A) (option B)

Doesn't affect (option A)

P(B|A) = P(B) (option A)

Explanation:

1) Conditional probabilities could be in the form P(A|B) or P(B|A)

P(B|A) is a notation that reads the probability of event B given that event A has occurred.

P(B|A) (option B)

2) Independent events do not affect the outcome of each other

For event A and B to be independent, the probability of event A occurring doesn't affect the the probability of event B occurring

Doesn't affect (option A)

3) Events A and B are independent if the following are satisfied:

P(A|B) = P(A)

P(B|A) = P(B)

The ones that appeared in the option is P(B|A) = P(B) (option A)

3 0
1 year ago
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sp2606 [1]

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