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madam [21]
3 years ago
10

Which is the way to express 10+12 as the product of the GCF and another sum?

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

The answer is pretty simple it's 12+10

Step-by-step explanation:

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table Given the graph of a linear function, identify the steps used to find the initial value. Check all that apply. Find the ra
Doss [256]

Answer:

  • The initial value corresponds to the y value when x = 0

Step-by-step explanation:

Since the graph is given, it is unnecessary to "finish the line." It is only necessary to read the value of y from the graph where x=0.

5 0
3 years ago
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A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Solve the system of equations.<br> y= 3x<br> y= x2-10
svetoff [14.1K]

Answer:

(-5, 2) and (2, 6)

Step-by-step explanation:

Use the substitution method. We know that y = 3x and y = x^2 - 10, so we can set them equal to one another.

3x = x^2 - 10

x^2 - 3x - 10 = 0

Use the quadratic equation to solve for x.

x = - 5, 2

Now solve for y using these two values of x by substituting it back into the equations.

y = - 15,  6

In coordinate form, (-5, 2) and (2, 6)

7 0
3 years ago
Please answer these and find the slope intercept form for each one.
damaskus [11]
1. 5/y=2/3x +3
2. y= 7/1-4
3. y=2/5x8
4. y=-3/4 +1 I could be wrong but I think this is right
5 0
2 years ago
Please help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vladimir2022 [97]
First one is 42
second is 24
Third is 12
3 0
2 years ago
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