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tester [92]
3 years ago
6

Find the average rate of change of the function f(x)=(1/x-7) as x changes from x=-2 to x=5

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0

Answer:

-\frac{1}{18}

Step-by-step explanation:

Average rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = -2,

f(a) = f(-2) = \frac{1}{(-2) - 7} = \frac{1}{-9} = -⅑

f(a) = -⅑

b = 5

f(b) = f(5) = \frac{1}{(5) - 7} = \frac{1}{-2} = -½

f(b) = -½

Plug in the values into the equation

Average rate of change = \frac{-\frac{1}{2} - (-\frac{1}{9}}{5 -(-2)}

= \frac{\frac{-9 - (-2)}{18}}{7}

= \frac{\frac{-7}{18}}{7}

= \frac{-7}{18} * \frac{1}{7}

= \frac{-1}{18} * \frac{1}{1}

= \frac{-1}{18} * 1

= -\frac{1}{18}

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88 = m - 12

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3 years ago
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About how much difference in average leaf width would you find in two forests whose average annual rainfalls are near 1500 mm bu
goblinko [34]

Answer:

4.80 mm to 2 d.p

Step-by-step explanation:

w = f(r)

f'(r) = (dw/dr) = (0.0218 mm/mm)

So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.

One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.

Mathematically,

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Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p

Hope this Helps!!!

5 0
3 years ago
The endpoints of EF<br> are E(1,3) and F(-2,8).<br> Find EF.
Phantasy [73]

Answer:

EF = \sqrt{34} ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = \sqrt{(-2-1)^2+(8-3)^2}

    = \sqrt{(-3)^2+5^2}

    = \sqrt{9+25}

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3 years ago
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Elis [28]

Answer:

D) y=5x+20

Step-by-step explanation:

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Suzanne gets 7% commission on all of her sales. If she makes a sale of $350,000, how much commission will she make?
sasho [114]

Answer:

$24,500 of commission

Step-by-step explanation:

350000*0.07 = 24,500

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2 years ago
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