Answer:12, 7
Step-by-step explanation:Using the process of elimination, I went through each number and subtracted five and added it until I got 12 and 7.
Answer:
quadrant 3
Step-by-step explanation:
you go to the left 1/2 and down 1.8, putting you in quadrant 3
Answer:
D. 
Step-by-step explanation:
Let be ![y = \Sigma_{i = 0}^{4} \left[5\cdot \left(\frac{1}{3} \right)^{i}\right]](https://tex.z-dn.net/?f=y%20%3D%20%5CSigma_%7Bi%20%3D%200%7D%5E%7B4%7D%20%5Cleft%5B5%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%5E%7Bi%7D%5Cright%5D)
. To find the equivalent expression we must use the following property:
![y = c\cdot \Sigma_{i = 0}^{n} p(x) = \Sigma_{i=0}^{n} [c\cdot p(x)]](https://tex.z-dn.net/?f=y%20%3D%20c%5Ccdot%20%5CSigma_%7Bi%20%3D%200%7D%5E%7Bn%7D%20p%28x%29%20%3D%20%5CSigma_%7Bi%3D0%7D%5E%7Bn%7D%20%5Bc%5Ccdot%20p%28x%29%5D)
(1)
Based on this fact, we find the following equivalence:
Hence, the correct answer is D.
To write this function in function notation all you would need to do is rearrange the equation for y.
3x + 2y = 12
3x - 3x + 2y = 12 - 3x
2y = 12 - 3x
2y/2 = 12/2 - 3x/2
Y = 6 - 3/2 X or
Y = -3/2 X + 6.
